pntr values move

[vinuk23]

I am trying to allocate values at two different stages of the code

//FIRST STAGE
pntr[0]->srvr->stage->final=(unihash*)malloc(sizeof(unihash)*(strlen(line2))*(cnt+2));
strcpy(pntr[0]->srvr->stage->final[cnt].key,first);
strcpy(pntr[0]->srvr->stage->final[cnt].value,secon);
free(pntr[0]->srvr->stage->final);
cnt++;

// SECOND STAGE
pntr[1]->srvr->stage->final = malloc(sizeof(unihash)*(9600)+1);
strcpy(pntr[1]->srvr->stage->final[cnt].key,first);
strcpy(pntr[1]->srvr->stage->final[cnt].value,secon);
free(pntr[1]->srvr->stage->final);
cnt++;

I find that when I try to access the pntr[1]->srvr->stage->final, all the key-values assigned to pntr[0]->srvr->stage->final[cnt].value
have moved to the pntr[1]->srvr->stage->final.

   
for(n=0 ; n < d; n++){
printf(" %d %d pntr[1]->bee->stg->maindbm %s %s \n",m,n,pntr[1]->bee->stg->maindbm[n].key,pntr[1]->bee->stg->maindbm[n].value);
             }

Is there any way I can keep the contents of pntr[0]->srvr->stage->final away from pntr[1]->srvr->stage->final.

[matsp]

free(pntr[0]->srvr->stage->final);

If you are going to use pntr[0]->srvr->stage->final after this point, then you should not free it. Likewise for pntr[1]...->final - do not free it if you are going to use it later on.

--
Mats

[vinuk23]

hi Kernel hacker,
I tried not freeing the
// free(pntr[0]->srvr->stage->final);
But I still get all the values moved over to
free(pntr[1]->srvr->stage->final);

Any other points that you can suggest....?

[matsp]

My guess would be that some other part of your (rather long) chain of pointers is also pointing to the wrong place or freed memory that is later on used for something else. Try stopping the second stage in the debugger, and compare the pointers at the different levels - if a pointer points to the same place in both pntr[1] and pntr[0], then that's obviously wrong [unless you really want to have the same information in both].


--
Mats

[vinuk23]

hi,
I have a little update.
I am pretty much using the same code as above (I commented the free statements)
I am able to get a saperate key-values for the
pntr[0]->srvr->stage->final
and
pntr[1]->srvr->stage->final

But now the problem is that the pntr[0]->srvr->stage->final
is able to save the list assigned to it and the
pntr[1]->srvr->stage->final has only the last of key value pairs assigned to it.

Could you suggest any thing from your vast experience....?

[vinuk23]

What I am saying is that the pntr[1]->srvr->stage->final is able to store only the last value assigned instead of the 7 key-values assigned to it.