here is the c program for arriving at a solution using bisection method.
The ouput is going infinte..pls help ....i think it has more of syntax errors than logical errors...
Code:main() { float a,b,c,x1,x2,x,series; double d; printf("enter a,b,c and x1(pos) & x2(neg)"); scanf("%f%f%f%f%f", &a, &b, &c, &x1, &x2); read: x = (x1 + x2) / 2; series = a * x * x + b * x + c; d = fabs(series); if (d > 0.0001) { if (x * x1 < 0) x = x2; else x = x1; goto read; } else { printf("ans=%f", x); } return 0; }
Last edited by swty_todd; 02-07-2009 at 09:39 PM.
main() - read FAQ
it should be
int main(void)
you should work on your indentation
if (x*x1<0) - you shoudl really think a little about this line
goto read; - there are several cases where usage of goto has its reasons. Your case is not one of these. So write your code using while loop
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
hey thnx vart.....!!!
hey i edited it ....bt its still not workin...help...
Code:#include<stdio.h> #include<math.h> main() {float a,b,c,x1,x2,x,series; double d; printf("enter a,b,c and x1(pos) & x2(neg)"); scanf("%f%f%f%f%f",&a,&b,&c,&x1,&x2); x=0; d=1; while(d>0.0001) { x=(x1+x2)/2; series=a*x*x+b*x+c; d=fabs(series); if(x*x1 < 0) x2=x; else x1=x; } printf("ans=%f",x); return 0; }
you have doe notinnk with the line
if(x*x1 < 0)
suppose x1 = 1, x2 = 3, than x = 2
think about right condition to get rid of the half of the interval
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
