warning: passing argument 1 makes pointer from integer without a cast

This is a discussion on warning: passing argument 1 makes pointer from integer without a cast within the C Programming forums, part of the General Programming Boards category; I get the above warning with the following code. I have used this same process in the past without any ...

  1. #1
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    warning: passing argument 1 makes pointer from integer without a cast

    I get the above warning with the following code. I have used this same process in the past without any warning. I have not been able to eliminate the warning.

    Code:
    //FUNCTION
    
    int FUPW_f(int *index, int i)   //Pulse Width Function
    	{	
    		int j;
    		int FPW;
    		if (i > 3) j = 1;
    		else j = 0; 		
    		FPW = *(index + j);
    		return FPW;
    	}
    //main
    
    int FULPW[8];
    int FUPW_REG[2];
    int PWOFF;
    
    
    for (i = 0; i < 8; i++)		
    	{
    		FULPW[i] = (FUPW_f(*FUPW_REG, i) + PWOFF);	
    	}
    	}

  2. #2
    C++ Witch laserlight's Avatar
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    FUPW_REG is an array of integers hence *FUPW_REG is the first integer in the array. FUPW_f's first parameter is a pointer to an integer, so what you should probably do is pass FUPW_REG instead of *FUPW_REG since the array would be converted to a pointer to its first element.

    By the way, a common convention is to reserve fully capitalised names for macro names.
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  3. #3
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    laserlight,

    When I do that, I get:

    warning: passing argument 1 of 'FUPW_f' discards qualifiers from pointer target type

  4. #4
    Frequently Quite Prolix dwks's Avatar
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    Perhaps you're passing a const pointer to a function that expects a non-const pointer?
    dwk

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    Quote Originally Posted by dwks View Post
    Perhaps you're passing a const pointer to a function that expects a non-const pointer?
    OK, that's it. I was passing a volatile integer to a non-volatile pointer. It's working now. Thanks.

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