Thread: No square displays

Hey guys.

I am having a problem making the square of characters appear at the end of the program. It compiles fine, but I get no output after input.
Any reason why?

I have accounted for the extra character in scanf() but it seems the program is totally ignoring the "let" char passed to it. I know the square "is" being drawn as to where the cursor is in the output, but the fill character is not being shown at all and I am getting no square.

This is my code, any help appriciated.

Code:

#include <stdio.h>

/*function prototype*/
void printSquare ( int, char );

/*main function - driver
**/
int main ( int argc, char *argv[] ) {
    int sideValue = 0;
    char filler = '\0';
    
    puts("Enter a side value:");
    scanf("%d", &sideValue);
    puts("Enter a single character:");
    scanf("% c", &filler);
    
    printf("\n");

    printSquare( sideValue, filler );
    
    getchar(); /*freeze console output*/
    getchar();
    
    return 0; /*return value from int main()*/
}

/*function to print a solid square of the character
  size based on the value passed*/
void printSquare ( int x, char let ) {
     getchar();
     int i,
         j;
         
     for ( i = 1; i <= x; i++ ) {
         for ( j = 1; j <= x; j++ )
            printf("%c", let);
         printf("\n");
     }
}

Thank you tabstop

Use gcc with the appropriate option to tell you about format strings perhaps?