what this warning means..

i defined

Code:

char opt[254];

on this line i get
|55|warning: char format, different type arg (arg 2)|

Code:

scanf("%s",&opt);

what that means??

&opt is not a pointer to char, which you need for the %s format specifier. You should use a pointer to char (in this case, "opt").

and as a side note - you should limit a number of chars that could be read by the format - to prevent buffer overrun

scanf("%253s",opt);

what will happen to the program if the user will enter 254 chars?

Your head will twist right off your body, and zoom into outer space!!

Try it and see.

The program will format your hard drive, too!
http://apps.sourceforge.net/mediawik...Buffer_overrun