Thread: How am I supposed to do this without a structure?

My instructor said I wasn't allowed to use a structure as we hadn't been taught it yet. So how am I supposed to read this from a file into an array?
It's set out like this
M 40 6
F 21 2
F 61 5
M 14 1

This is what I have but of course it won't work properly as the first data type is char not int

Code:

#include <stdio.h>

#define RECORDS 200
#define FIELDS 3

void read_file();

int main()
{
   read_file();
}

void read_file()
{
   FILE *fpin;

   int rec[RECORDS][FIELDS];
   int m, n;

   fpin = fopen("custsurvey.dat", "r");

   if(fpin == NULL)
   {
      printf("Error opening file");
   }
   else
   {
      for(m = 0; m < RECORDS; m++)
      {
         for(n = 0; n < FIELDS; n++)
         {
            fscanf("%d", &rec[m][n]);
         }
      }
   }
   fclose(fpin);
}

Parallel arrays is the norm before studying structs with one array. Your first array will be type char, your others will be type int. char array[i] and int array1[i], int array2[i], etc., will all refer to the same record (person), and will be used as fields in a record or members in a struct.

What you could do is write 1 into the array if it is M and 2 if it is F.



maybe

Code:

      for(m = 0; m < RECORDS; m++)
      {
         char sex;

         fscanf("%c %d %d\n", &sex,   &rec[m][1],   &rec[m][1]   );
         if (sex=='M') rec[m][0]=1;
         if (sex=='F') rec[m][0]=2;
         if ( sex!='M' || sex!='F') printf("\nOh dear!!");


    }

Ok. Esbo I had had that idea but wasn't sure how to do it. Thanks.

Originally Posted by esbo

Code:

...
         if ( sex!='M' || sex!='F') printf("\nOh dear!!");
...

esbo, your if condition will always result in TRUE. I guess you meant:

Code:

if ( sex!='M' && sex!='F') ...