well i have a similar but a bit different problem .
i am using visual c++ , ver 6.0 .
when i execute this code it wont take float input ??
i have tried debugging it says 'no return address"
Code:case 2 : { printf("\n Set laser pulse delay stepping from 1.25ns to 0.25ns : "); scanf("%f", &ds); delaa(); // just a delay function break; } // all the other cases work fine ???
Split from http://cboard.cprogramming.com/showthread.php?t=110458
You're going to have to post more code than that.
Ideally, something which compiles.
For example, what type is ds?
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Is there a specific reason you use VS6? Can you upgrade to a more modern compiler?
Originally Posted by Adak
Here's the begining of the code:
Code:#include "stdafx.h" // it contains all the headers . int usrchoice(void); // takes input for defining parameters for otdr opration void delaa(void); // just a delaa function unsigned long pw; float ds = 0.0; unsigned int il; double avg; main( ) { while(1) { // get user selection and branch to that task. switch(usrchoice()) { case 1 : { printf("\n Set laser pulse width b/w 10ns to 1000ns(10us) : "); scanf("%d", &pw); delaa(); break; } case 2 : { printf("\n Set laser pulse delay stepping from 1.25ns to 0.25ns : "); scanf("%f", &ds); delaa(); break; }
when it is run it and takes input on case 2 , it comes up with runtine error ???
Last edited by Asimghouri; 01-13-2009 at 03:10 PM. Reason: more info
