adding elements in array

I'm making a program that will add all the values in an array to get a total value, I wrote out my program on paper and it should run just fine, but instead of the final variable of the array just getting a total value of all integers, it gets the first value of the array. Here's my program:
Code:

Code:

#include <stdio.h>

void main()

 // bcc32 -IC:\Borland\bcc55\include -LC:\Borland\bcc55\Lib register2.c  to compile


{	
	int	a[1000], b, c=0, d[1000], i=0,  f[1000];  // these elements are for later
	float	e;

	printf("Please enter the price of the item and hit 0 to quit:$");
	scanf("%d", &a[i]);	
	
		while(a[i]!=0)
		{
		
			if(i==0)
			{
			i++;
			}
		    
		printf("Please enter the price of the item and hit 0 to quit:$");
		scanf("%d", &a[i]);		// filling array values
		
		
		
			if(a[i]!=0)
			{
			a[i+1]=a[i]+a[i-1];
			i+2;	// adding array values
			}
		
		}
			
		
	printf("\nThe total is $%d", a[i-1]);
}		                                      // end program

The second if statement is where I'm having trouble.
When I write it out it should run like this: i=0, a[0]=1, i=1, a[1]+a[1-1]=a[1+1]
i=3, a[3]=2, a[3+1]=a[3]+a[2] etc.

Seems like you're trying to implement a Fibonacci sequence!
Anyway, that does "i+2" mean? If you want to increment i by 2 the way to do it is

Code:

i = i + 2

A few things that will help you:

• Indent your code properly. This will allow you to more clearly see the structure of your loops and if statements.
• Only declare the variables that you need now. If you need variables later, add them in later.
• Although on a technicality it is possible to argue the contrary, the main function is supposed to return an int, to declare it as such, and return 0 at the end.

The second time your program reaches the loop header, i is 3, and a[3] is undefined at this point.
By pure chance a[3] is 0 and the execution stops.

Originally Posted by Leojeen

Seems like you're trying to implement a Fibonacci sequence!
Anyway, that does "i+2" mean? If you want to increment i by 2 the way to do it is

Code:

i = i + 2

Thanks, that fixed it!

It looks like I'm going to beat Elisia to saying it this time:

main must return int, not void.

Originally Posted by iMalc

It looks like I'm going to beat Elisia to saying it this time:

main must return int, not void.

Unfortunately, you lost to me, as per post #3