' assignment makes pointer from integer without a cast "

This is a discussion on ' assignment makes pointer from integer without a cast " within the C Programming forums, part of the General Programming Boards category; Hi All, Greeting! I am getting this error " assignment makes pointer from integer without a cast" for this line. ...

  1. #1
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    ' assignment makes pointer from integer without a cast "

    Hi All,
    Greeting!
    I am getting this error " assignment makes pointer from integer without a cast" for this line.

    Code:
    root=addtree(root,job);
    Declaration for addtree is as follows
    Code:
    Tree_ptr addtree(Tree_ptr ,char *);
    and Tree_ptr is
    Code:
    typedef struct tree_node
    {
    	char *word;
    	int index;
    	struct tree_node *left;
    	struct tree_node *right;
    }Tree;
    
    typedef struct tree_node *Tree_ptr;
    .

    and Declaration for root is
    Code:
    Tree_ptr root;
    The whole point is to return a pointer to a structure tree_node. I am just trying to learn typedef. Could some one please explain what is wrong with this declaration?

  2. #2
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    hmm, compiling on linux with command and options "gcc str.c -Wall -pedantic" gives no errors or warnings. this is what i am compiling, of course based on your code snippets:
    Code:
    typedef struct tree_node
    {
    	char *word;
    	int index;
    	struct tree_node *left;
    	struct tree_node *right;
    }Tree;
    
    typedef struct tree_node *Tree_ptr;
    
    Tree_ptr addtree(Tree_ptr ,char *);
    
    int main()
    {
        char * job;
        Tree_ptr root;
        root=addtree(root,job);
        return 1;
    
    }
    
    Tree_ptr addtree(Tree_ptr a,char *b){
        return a;
    }
    is "job" of correct type? what compiler are you using?

  3. #3
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    Quote Originally Posted by nadroj View Post
    hmm, compiling on linux with command and options "gcc str.c -Wall -pedantic" gives no errors or warnings. this is what i am compiling, of course based on your code snippets:
    Code:
    typedef struct tree_node
    {
    	char *word;
    	int index;
    	struct tree_node *left;
    	struct tree_node *right;
    }Tree;
    
    typedef struct tree_node *Tree_ptr;
    
    Tree_ptr addtree(Tree_ptr ,char *);
    
    int main()
    {
        char * job;
        Tree_ptr root;
        root=addtree(root,job);
        return 1;
    
    }
    
    Tree_ptr addtree(Tree_ptr a,char *b){
        return a;
    }
    is "job" of correct type? what compiler are you using?
    I am using gcc. Your code doesn't give me any error or warning.. Job is char *. Let me see what is wrong with mine.

  4. #4
    cas
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    One possibility is that you're using addtree() without declaring it; that is, you forgot to include whatever header contains a prototype for it. In the absence of a declaration, the compiler will assume the function returns int, and you'd get the message you describe above.

    While it's technically legal to use (some) functions before declaring them, such uses should always be considered bugs, and fixed. GCC will tell you about such implicit declarations if you use the -Wall flag. Really, you should always, always, always build with at least the -Wall flag, as it will alert you to all sorts of potential problems.

  5. #5
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    Quote Originally Posted by cas View Post
    One possibility is that you're using addtree() without declaring it; that is, you forgot to include whatever header contains a prototype for it. In the absence of a declaration, the compiler will assume the function returns int, and you'd get the message you describe above.

    While it's technically legal to use (some) functions before declaring them, such uses should always be considered bugs, and fixed. GCC will tell you about such implicit declarations if you use the -Wall flag. Really, you should always, always, always build with at least the -Wall flag, as it will alert you to all sorts of potential problems.
    Thanks!
    Yes, You are right. I missed the function declaration in the header file.
    Thanks to all for their kind help.

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