how to sort the matrix so the sums of the rows
will go from the biggest sum on the bottom
to the smallest on top
like in this example:
http://img101.imageshack.us/img101/4580/79171873gv6.gif
how to sort the matrix so the sums of the rows
will go from the biggest sum on the bottom
to the smallest on top
like in this example:
http://img101.imageshack.us/img101/4580/79171873gv6.gif
Last edited by transgalactic2; 12-20-2008 at 10:06 PM.
Just like you would sort anything else. You can use bubblesort, quicksort, insertion sort, ..., ..., ..., ..., ....
in pseudo code
This is a selection sort, and is not meant as actual code to paste into a program. You'll need to flesh it outCode:for each column { for i = 0; i < Num of rows - 1; i++) { for j = i + 1; j < Num of rows; j++) { if(Array[column][i] > Array[column][j] swap Array[i][column] with Array[j][column] //using a temp value as a holder } } }
with real, not pseudo code, but it's pretty much there.
Last edited by Adak; 12-20-2008 at 04:34 PM.
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
I just glanced at his jpg and thought he was trying to do a column sort.
My intent was that he notice that since it's a square matrix, you could swap column and row, but I'm not sure that will fly, here.
The craft of writing good pseudo code eludes me. generally. It's either too general, so the specifics are not to be relied on, or it's too specific, and then it is code. The latter is usually quite close, the former is never quite right, and I frequently find it a happy spot in the trash bin.
i need to do row sort
and the matrix doesnt have to be square
Consider each row as it's own string:
The red code handles the rows, the blue part is the standard selection sort for a single dimension array.Code:for each row sort each cell in that row which might look like: for(r = 0; r < MaxRows; r++) { for(i = 0; i < MaxCols - 1; i++) { for(j = i + 1; j < MaxCols; j++) { if(A[r][i] > A[r][j] { temp = A[r][i]; A[r][i] = A[r][j]; A[r][j] = temp; } } } }
Edit:
Your picture you linked to in your original post, does not show an array that is row sorted. It shows an array that has been sorted according to the sum of it's rows. That is not what the code above, will do. The above code will move all the lower numbers for each row, to the left position in that row, in ascending order.
To do a row-sum sort, you will compare only each row's sum, and when they are out of order, with another row, you'll swap the two rows - including all the column values, all the way across the rows.
For each row: compute a sum. Put the value in a small sum[] array, of one dimension.
Now you can do your sorting. The slick way to do this is to use an index, and then you show the sorted array by printing it up in the order of the index.
I am not going to show that, because it's above your coding experience, just yet. For now, just know that there is a sort through an index, that involves making no actual swaps in the array at all, but will show the array *as if* it was sorted, in perfect order.
I haven't run this code, but it looks OK. Isn't that style of indentation (K&R), easy to read? I liiiiiike it!Code:for(i = 0; i < MaxElementsofSum[] - 1; i++) { for(j = i + 1; j < MaxElementsofSum[]; j++) { if(Sum[i] > Sum[j]) { temp = Sum[i]; Sum[i] = Sum[j]; Sum[j] = temp; //now swap the rows elements, from row j to row i for(k = 0; k < MaxColumnsofMatrix[]; k++) { temp = Matrix[i][k]; Matrix[i][k] = Matrix[j][k]; Matrix[j][k] = temp; } } } }
Last edited by Adak; 12-21-2008 at 03:58 AM.
i created an array rows_sum which collects the sums of each row
what to do now
Code:#include <stdio.h> int main(){//star int rows,cols,jndex,input; int sum2=0; printf("enter rows and cols [1..50] ==> "); scanf("%d %d",&rows,&cols); int matrix[rows][cols]; int sum[rows][cols]; int temp[rows][cols]; int transpose [cols][rows]; int index,kndex,tndex,gndex,lndex; int rows_sum[rows]; printf("enter power:"); scanf("%d",&input); for (index = 0; index < rows; index++) { rows_sum[index]=0; for (kndex = 0; kndex < cols; kndex++) { matrix[index][kndex] = 0; sum[index][kndex] = 0; temp[index][kndex] = 0; transpose[index][kndex] = 0; }//end inner for }//end outer for printf("enter numbers in a row for a matrix:"); //stat input for (index = rows - 1;index >= 0; index--) { for (kndex = cols - 1; kndex >= 0; kndex--) { scanf("%d", &matrix[index][kndex]); transpose[kndex][index] = matrix[index][kndex]; } } getchar(); //needed because of scanf() //end input //start power operation // rows sum for (index = 0; index < rows; index++) { for (kndex = 0; kndex < cols; kndex++) rows_sum[index]=rows_sum[index]+matrix[index][kndex]; printf("\n"); } // end rows sum //start print for (index = 0; index < rows; index++) { for (kndex = 0; kndex < cols; kndex++) printf("%d ", sum[index][kndex]); printf("\n"); } //end print printf("\n"); return 0; }//end main func
When you want to sort the rows, according to their sums, just copy and paste my code into your program, and check that the Matrix() and the Sums[] arrays in your program, and in my block of code, have the same names.
My block of code, should not go inside any loops in your program, of course. Then check that the variables I used: i, j, temp, etc., are declared in your program.
When you want to then print out your matrix, just print it out the normal way, don't use the row_sums array to print out the sorted matrix - no need for that. The whole matrix is already in row-sum order.
Last edited by Adak; 12-21-2008 at 02:01 PM.
I know that "sum[i]" is the sum of row "i"
what is purpose of this array MaxElementsofSum[] ??
and why you dont put any value in it when you construct a loop with it
Code:for(i = 0; i < MaxElementsofSum[] - 1; i++) { //there is no value inside the cols for(j = i + 1; j < MaxElementsofSum[]; j++) { //what is the purpose of MaxElementsofSum if(Sum[i] > Sum[j]) { temp = Sum[i]; Sum[i] = Sum[j]; Sum[j] = temp; //now swap the rows elements, from row j to row i for(k = 0; k < MaxColumnsofMatrix[]; k++) { temp = Matrix[i][k]; Matrix[i][k] = Matrix[j][k]; Matrix[j][k] = temp; } } } }
Last edited by transgalactic2; 12-21-2008 at 02:23 PM.
This is the index sort I referred to earlier. It doesn't sort the matrix at all, but sorts a small index, instead.
That index array can be used to print out the matrix, just like it was sorted.
Say that you have an array of three friends ages, and a corresponding array of their names:
So Adam is 30, Kevin is 20, and Zoi is 40. Now we want to print out our friends, sorted by age, but not mess with changing the original age[] or names[] arrays.Code:int ages[3] = { 30, 20, 40 }; char names[3][25] = { { "Adam" }, {"Kevin" }, {"Zoi" } };
First we need an index array, initialized in sorted order:
Code:int index[3]; //initialize it for(i = 0; i < sizeOfIndex; i++) index[i] = i; //Now we sort, using that index: for(i = 0; i < sizeOfIndex - 1; i++) { for(j = i + 1; j < sizeOfIndex; j++) { if(age[index[i]] > age[index[j]] { //I'm comparing ages, through the index array temp = index[i]; index[i] = index[j]; //only the index contents are swapped index[j] = temp; } } } //now print out the data, in sorted order, by going through the index array. putchar('\n'); for(i = 0; i < sizeOfIndex; i++) printf( " Age: %d Name: %s \n", age[index[i]], names[index[i]] ); //showing: Age: 20 Name: Kevin Age: 30 Name: Adam Age: 40 Name: Zoi /* Original arrays still are in their original order: 30 Adam 20 Kevin 40 Zoi */
Last edited by Adak; 12-21-2008 at 02:38 PM.
This code:
MaxElementsOfSum[] is the number of elements in the Sum[] array, which hold a sum in them. In your exampleCode:for(i = 0; i < MaxElementsofSum[] - 1; i++) { for(j = i + 1; j < MaxElementsofSum[]; j++) { if(Sum[i] > Sum[j]) { temp = Sum[i]; Sum[i] = Sum[j]; Sum[j] = temp; //now swap the rows elements, from row j to row i for(k = 0; k < MaxColumnsofMatrix[]; k++) { temp = Matrix[i][k]; Matrix[i][k] = Matrix[j][k]; Matrix[j][k] = temp; } } } }
with a 4 X 4 matrix, you would have 4 elements in Sum[].
i tried to implement that
sum is an array which holds the sum of each row
i switched MaxColumnsofMatrix[] by "rows" (because rows is the number cells in the sum array)
but i get many error of this type
ex2.c(62) : error C2109: subscript requires array or pointer type
Code:#include <stdio.h> int main(){//star int rows,cols,jndex,input; int sum2=0; printf("enter rows and cols [1..50] ==> "); scanf("%d %d",&rows,&cols); int matrix[rows][cols]; int sum[rows][cols]; int temp[rows][cols]; int transpose [cols][rows]; int index,kndex,tndex,gndex,lndex; int rows_sum[rows]; printf("enter power:"); scanf("%d",&input); for (index = 0; index < rows; index++) { rows_sum[index]=0; for (kndex = 0; kndex < cols; kndex++) { matrix[index][kndex] = 0; sum[index][kndex] = 0; temp[index][kndex] = 0; transpose[index][kndex] = 0; }//end inner for }//end outer for printf("enter numbers in a row for a matrix:"); //stat input for (index = rows - 1;index >= 0; index--) { for (kndex = cols - 1; kndex >= 0; kndex--) { scanf("%d", &matrix[index][kndex]); transpose[kndex][index] = matrix[index][kndex]; } } getchar(); //needed because of scanf() //end input //start power operation // rows sum for (index = 0; index < rows; index++) { for (kndex = 0; kndex < cols; kndex++) rows_sum[index]=rows_sum[index]+matrix[index][kndex]; printf("\n"); } // end rows sum int i,j,k,temp; for(i = 0; i <rows - 1; i++) { for(j = i + 1; j <rows; j++) { if(rows_sum[i] >rows_sum[j]) { temp = rows_sum[i]; rows_sum[i] = rows_sum[j]; rows_sum[j] = temp; //now swap the rows elements, from row j to row i for(k = 0; k <rows; k++) { temp = matrix[i][k]; matrix[i][k] = matrix[j][k]; matrix[j][k] = temp; } } } }
Last edited by transgalactic2; 12-22-2008 at 01:40 AM.
So far as I can tell, line 62 is the penultimate closing brace. If you're going to remove lines so that we can't count, you'll have to tell us what line line 62 actually is.