how to change it into one main() function code..

Code:

---

#include <stdio.h>

int flip (int num);

int main (void) {
  int i, j, c = 0;

  printf( "\nEnter the number to flip: ");
  scanf( "%d", &i);

  while (i != flip(i)) {
    j = flip(i);
    printf( "%d + %d = %d\n", i, j, i+j);
    c++;
    i += j;
  }

  printf( "Completed in %d steps.\n", c);
  return 0;
}

int flip (int num) {
  int digit, result = 0;

  while (num != 0) {
    digit = num % 10;
    result = result * 10 + digit;
    num /= 10;
  }

  return result;
}

---

Integrate the flip() function into the while loop.

Frankly, I think you are really learning C the wrong way round.

i tried in every form possible

i tried to put before and after
and use a temp variables
and nothing gives me the same result

Rewrite the original code such that you only call flip(i) once in the loop (you should be doing that anyway). Additionally, do not call it within the loop condition (this will make it easier for you to integrate flip() into the loop).

i tried like you said
it doesnt work as before

Code:

---

#include <stdio.h>



int main (void) {
  int i, j, c,l = 0;
int digit, result = 0;


  printf( "\nEnter the number to flip: ");
  scanf( "&#37;d", &i);


  digit=0;
  result=0;
  while (i != 0) {
    digit = i % 10;
    result = result * 10 + digit;
    i /= 10;
  }

l=result;

  while (i != l) {


        digit=0;
  result=0;
  while (i != 0) {
    digit = i % 10;
    result = result * 10 + digit;
    i /= 10;
  }

    j = result;
    printf( "%d + %d = %d\n", i, j, i+j);
    c++;
    i += j;
  }

  printf( "Completed in %d steps.\n", c);
  return 0;
}

---

thanks for pointing me to the correct thread laserlight.

As I noted, rewrite the code such that you only call flip(i) once in the loop. It is convenient if you do not call flip(i) outside of the loop either. It is even more convenient if flip(i) is the first thing in the loop body. I would use a controlled infinite loop, but a do while loop would also work:

Code:

---

#include <stdio.h>

int flip(int num);

int main(void) {
    int i, j, c = 0;

    printf( "\nEnter the number to flip: ");
    scanf( "&#37;d", &i);

    do {
        j = flip(i);

        if (i != j) {
            printf( "%d + %d = %d\n", i, j, i+j);
            c++;
            i += j;
        }
    } while (i != j);

    printf( "Completed in %d steps.\n", c);
    return 0;
}

int flip(int num) {
    int digit, result = 0;

    while (num != 0) {
        digit = num % 10;
        result = result * 10 + digit;
        num /= 10;
    }

    return result;
}

---

The transformation is a matter of cut and paste: you just need to assign i to num and result to j.

By the way: how long more before you are allowed to use functions? If it is not soon, just quit the class: there is no point learning C without the use of proper abstraction being taught.

i solved this problem thanks :)

Quote:

---

Originally Posted by transgalactic2

i solved this problem thanks :)

---

YOU solved it?!? LOL! (just kidding) Congrats!

Laserlight: Thanks for pointing out how *not* to call the flip function twice. I should have known better. There are a lot of smart people posting here. I think I will enjoy this forum a lot.

-Dave

And when will you learn proper indentation, transgalactic2?

Quote:

---

Originally Posted by mutandis

Laserlight: Thanks for pointing out how *not* to call the flip function twice. I should have known better.

---

Actually, if transgalactic2 was not trying to "undo the abstraction" by removing the flip() function call, I would rather have called flip() in two places:

Code:

---

j = flip(i);
while (i != j) {
    printf("%d + %d = %d\n", i, j, i+j);
    c++;
    i += j;
    j = flip(i);
}

---