Help, how to distill date from time_t value?
This is my code below:
Its output is something like "Sat Dec 18 12:38:38 1971". I only want the date portion to be outputted, i.e. Dec 18 1971. Can anybody help me!Code:time_t now = time(NULL); printf("%s\n", ctime(&now));
Any help is appreciated!
strftime will take a struct tm and a format string (like printf sort of), which you can get by calling localtime or gmtime.
Or you could just use sprintf() with the data in struct tm, since it gives you year, month, day, etc.
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
Thank you so much!
I put my code here to help others who need this two.
NOTE: The returned pointer from localtime is a static variable, that means it might be overwritten by subsequent calls to ctime, gmtime, or localtime.Code:char date_buff[40]; time_t time_value = time(NULL); struct tm* my_tm = localtime(&time_value); strftime(date_buff, sizeof(date_buff), "%b %d,%Y\n", my_tm); printf("%s\n", date_buff);
