Caesar Cipher

This is a discussion on Caesar Cipher within the C Programming forums, part of the General Programming Boards category; I need to make an encrypt/decrypt Caesar algorithm that asks for the user to put in a key. The following ...

  1. #1
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    Caesar Cipher

    I need to make an encrypt/decrypt Caesar algorithm that asks for the user to put in a key. The following is what I have so far, I started off doing a rot-13 and tried to progress but as you can see, ran into a couple of problems. It is not complete yet because I have to ask for character input, but I'm having trouble seeing where I need to add a string array. Can anyone point me in the right direction and maybe give me a hint on what to do? Thanks.

    Code:
    #include<stdio.h>
    
    
    int main()
    int crypt;
    int x,y;
    int key;
    char input;
    {
    	printf("Do you want your characters encrypted [1] or decrypted [2]? \n");
    	scanf("%d", crypt);
    	printf("Enter a key");
    	scanf("%d", key);
    
        while((x=getchar())!=EOF && crypt=1)
    	{
    		printf("Enter data to encrypt.\n");
    		fflush(stdin);
        	gets(input);
    		if(x >='A' && x <='Z')
    		{
    			if((y = x + key) <= 'Z')
    				putchar(y);
    			else
    			{
    				   y = x - key;
    				putchar(y);
    			}
    		}
    		else if(x >='a' && x <='z')
    		{
    			if((y= x + key) <= 'z')
    				putchar(y);
    			else
    			{
    				y = x - key;
    				putchar(y);
    			}
    		}
    		else
    			putchar(x);
    	}
    
    return 0;
    }

  2. #2
    and the Hat of Guessing tabstop's Avatar
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    Since there is no such thing as a string array, adding one will be very difficult.

    So in your input thing, you can read a character at a time if you want, there's nothing stopping you. If you want to read in a line at a time, then make input an array of char instead of just a single char.

    And there is no correct way to use gets.

  3. #3
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    You need to learn about scanf.

    Code:
      scanf("&#37;d", &digit);
    
      scanf("%c", &char);
    
      scanf("%s", char array);
    The ampersand char in C means "the address of". Since array names ARE their address, they don't
    need an ampersand before them when in scanf().


    That should help.

  4. #4
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    So, does that mean my variables are okay? I'm really confused now because I missed the class my teacher went over character arrays and the book is not helping much. I think the "gets" thing was a typo my teacher made, but he said we needed that to scan for a whole line and not just the first word.

  5. #5
    and the Hat of Guessing tabstop's Avatar
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    You would then need to make x travel through each character in the input array. You would also need to encrypt using a caesar cipher correctly. (Hint: y = x - key is not using a caesar cipher correctly.)

  6. #6
    Banned master5001's Avatar
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    Would it not be faster to have something like:

    Example:
    Code:
    static unsigned char ascii[256];
    
    int init(int seed)
    {
      register unsigned char *s = ascii, uc_seed = (unsigned char)seed;
      register const unsigned char *end = ascii + sizeof(ascii);
    
      for(;s < end;)
        *s++ = uc_seed++;
    }
    Then you would simply just encode by saying ascii[letter_you_wish_to_encode].

  7. #7
    and the Hat of Guessing tabstop's Avatar
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    Except for "punctuation doesn't change" and "arithmetic mod 26" parts.

  8. #8
    Banned master5001's Avatar
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    Oh well, I guess this is what happens when you only deal with me when it is the end of the day and I am tired.

  9. #9
    CSharpener vart's Avatar
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    Code:
    int main()
    int crypt;
    int x,y;
    int key;
    char input;
    since when the main has such strange number of parameters?

    it should be
    Code:
    int main(void)
    {
       int crypt;
       int x,y;
       int key;
       char input;
       etc...
    fflush(stdin); - undefined - read FAQ

    crypt=1 - this is assignment you want crypt==1
    The first 90% of a project takes 90% of the time,
    the last 10% takes the other 90% of the time.

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