Pointers not opening file

I'm trying to create a program that would first read a list from a data file containing names of people and their sales and then calculate the amount of commission each person makes. I'm trying to get the program to print the information on the screen and then print the same info on a separate data file but currently the gcc compiler would kill the process.

Code:

#include <stdio.h>
int main(){
int k;
char text[81], name[30], surname[30];
double sale, comission;
FILE *Inf_1, *Outf_1;
Inf_1 = fopen("Sales.dat", "r");
Outf_1 = fopen("Comiss.dat", "w");

if ((Inf_1 == NULL) || (Outf_1 == NULL))
	{
		printf("Error opening the file\n");
		exit(1);
	}
while(fgets(text,81,Inf_1)!=NULL)
	{
		k++;
		if (k%2 !=) {
		   sscanf(text, "%s %s", name, surname);
		else
		{
		 sscanf(text, "%lf", &sale);
		 if (sale <= 25000) {
			comission = sale * .06;
             }
		 if (sale > 25000 && sale <= 50000) {
			comission = sale * .09;
             }
		 if (sale > 50000 && sale <= 80000) {
			comission = sale * .12;
             }
		 if (sale > 80000) {
			comission = sale * .14;
             }
		printf("\n%s %s\n", name,surname);
		printf("The comission of Mr/Ms %s is %f, based on the sale of %f\n", surname, comission, sale);
		fprintf(Outf_1, "The comission of Mr/Ms %s is %f, based on the sale of %f\n", surname, comission, sale);
                  }
  }
	fclose(Inf_1);
	fclose(Outf_1);
	exit(0);
}
}

DevC++ is giving me the following errors:
18 hw6.c
parse error before `)'
40 hw6.c
warning: parameter names (without types) in function declaration
40 hw6.c
warning: data definition has no type or storage class
41 hw6.c
warning: parameter names (without types) in function declaration
42 hw6.c
parse error before `0'
42 hw6.c
warning: data definition has no type or storage class

I am currently in the middle of solving the bracket issues (at this moment, not very good at formatting on a UNIX platform) but I'm not sure how to solve the data definition errors. Any input?

This line of code is incomplete:

Code:

if (k%2 !=) {

And, if you fix your indentation, you will see your braces are not placed properly.

... damn.

A development process

Code:

for ( ; ; ) {
}
while ( 0 ) {
}
if ( 0 ) {
}

Believe it or not, this will compile.

What it does mean is that your ( ) and { } are NEVER out of balance. Sure it's a few extra cursor movements (if you don't have a smart code editor which auto-inserts the construct for you), but it sure beats spending hours of "hunt the missing }" in a chaotically indented program, then giving up and posting the whole mess on a message board for someone else to figure out.

The same goes for "" and /**/ and #if/#endif as well.
If you keep them balanced from the outset, then you don't have to keep a mental stack of what the current nesting level is.