I have something like this,
Code:int main(void) { int x[100]; // loop and scanf to get user input for array } int calculate( x[100] ) { //variable passed from main function into this function //bunch of code here to do calculation return (x[100]); }
basically all I'm trying to do it pass a variable from main function to calculation function.
I'm reading my text....and I kinda think I got the concept wrong...
Luckily your compiler should warn you about that. You are somewhat on the right track already. Just call the function like calculate(x);Code:int main(void) { int x[100]; // loop and scanf to get user input for array } int calculate( x[100] ) { //variable passed from main function into this function //bunch of code here to do calculation return (x[100]); }
Originally Posted by master5001
why did you highlight the 100?
I don't know what you mean.....
I been getting a bunch of compiler errors....but the program itself works flawlessly.
As he said in the text right below the program, it needs to be removed from your program.
Then you probably did.
The type of the parameter 'x' in calculate is missing, it should be int by the looks of it.
Returning x[100] is a buffer overflow because arrays start at zero so you're actually returning item 101 of an array with only 100 items. That's why it is red.
The program possibly works flawlessly because you don't call the function with the buffer-overrun.
If you want to demonstrate the concept of functions, then you really need to actually call the function.
My homepage
Advice: Take only as directed - If symptoms persist, please see your debugger
Linus Torvalds: "But it clearly is the only right way. The fact that everybody else does it some other way only means that they are wrong"
How can you run a program that has compiler errors?
QuantumPete
"No-one else has reported this problem, you're either crazy or a liar" - Dogbert Technical Support
"Have you tried turning it off and on again?" - The IT Crowd
Another problem is that you didn't specify a type for the parameter.Code:int calculate( int x[100] )
"I am probably the laziest programmer on the planet, a fact with which anyone who has ever seen my code will agree." - esbo, 11/15/2008
"the internet is a scary place to be thats why i dont use it much." - billet, 03/17/2010
dam Xcode....
I thought I was running it...but in fact, the terminal that ran ...ran the code I had working before I split my program into functions.
I got it working now....some of it atleast.
scrap what I had in the first post, I was tryng to summarize the code so it isn't so long
this is what I should have posted in the beginning...
Code:int main(void) { int x[100]; // loop and scanf to get user input for array // ????? what do I put here to get output from the checker(function 2) function? } int calculate( x[100] ) //function 1 { //variable passed from main function into this function //using this array, do a bunch of calculations tempvar = x[25] * 10 return (tempvar); } int checker() //function 2 { //I want to receive tempvar from the calculate function into this function //I also need the x[100] also }
This should be of help: http://www.cprogramming.com/tutorial/c/lesson4.html
I hate to by the guy asking for help, and not bothering to search for answers myself....
but....I have three reference books, and I still can't figure this out. *very close to calling it quits
I'm gonna go through the link, hopefully I figure this out....thnkx.
If you can't figure it out even with the link just keep adding to the thread. The whole point of a forum is for the extra level of interaction and the ability to simply "still not get it." We are the absolute last line of defense that lies between where you are now and giving up.
^your absolutly right
I'm just a little frustrated....
I decided I have the whole concept wrong, and I am gonna start from scratch.
now here, scratching my head once again:
it seams impossible, but the first printf statement prints a number different from the second printf(3rd LOC). How can that middle line have any influence in the array?Code:printf("The entered isbn 10th digit is %d\n" , isbn[9]); ldigit = 11 - (sum)%11; printf("The entered isbn 10th digit is %d\n" , isbn[9]);
How would we know? Maybe isbn[9] doesn't exist.
Re: your original question...
When you declare and define a function, you specify its return type, as well as the types of the parameters to the function, to which you can pass arguments.
return_type function_name(parameter_type parameter_name, ...)
To return something from a function, you would use the "return" statement.
T get something returned from a function, you would assign it to a variable:
my_var = myfunctioncall(...);
Now my_var will contain whatever myfunctioncall returned.
And you also know that you can pass argument to a function:
myfunctioncall(arg1, arg2);
The arguments you pass shall match the type you decided in the declaration. So if you know you are going to pass a char array to it, then you declare the type of one parameter to such a type to be able to handle a char array.
