Thread: decimal to hexadecimal

I already understand how to convert it into it's numerical value, but i dont understand how to display the result into it's alphabetical value.
like the hexadecimal value of 26 = 1A.
i'm stuck at displaying the value as 26 = 110.

this is how i do so far :

can someone please point out my mistake ?

Code:

#include <stdio.h>

int main ()
{

	int ask = 26;
	int a;
	int b[9];
	int c = 0;
	
	while ( ask > 0 ) {
	
		a = ask % 16;
		if ( a == 10 ) {
			
			b[c] = 'A';
			}
		
		if ( a == 11 ) {
		
			b[c] = 'B';
			}
			
		if ( a == 12 ) {
		
			b[c] = 'C';
			}
		
		if ( a == 13 ) {
		
			b[c] ='D';
			}
			
		if ( a == 14 ) {
		
			b[c] = 'E';
			}
		
		if ( a == 15 ) {
			
			b[c] = 'F';
			}
			else {
				
				b[c] = a;
				}
		
		c++;
		ask = ask / 16;
		
		
		}
		
		while ( c ){
		
		printf ("%d", b[--c]);
		
		}
		getchar ();
    return 0;
}

All your good work gets undone by the last else -- that else is only on the if a==15; if you've already set b[c] to 'A', well, too bad.

i try to replace that last else with

Code:

if ( a < 10 ) {

   b[c] = a;
   }

the result was still wrong. it end up displaying 165. any other suggestion ?

Originally Posted by prominababy

i try to replace that last else with

Code:

if ( a < 10 ) {

   b[c] = a;
   }

the result was still wrong. it end up displaying 165. any other suggestion ?

Well, that's what you wanted, wasn't it? 'A' is 65, after all.[0] If you want letters, why would you be printing ints with %d?

[0]Obviously only on ASCII machines, but that's apparently what we're on.