My switch statement embedded in my do loop doesn't seem to execute correctly:

Instead of correctly recognizing the "#" term approximation, it prints a blank line. Anyone have some input?Code:`#include <stdio.h>`

#include <math.h>

int main()

{

double x, y, y2;

int n_term;

printf("Enter -1<x<1 : ");

scanf("%lf",&x);

y = log (x);

printf("\nTrue value of log(1+x) = %.5f\n\n",y);

do {

printf("Enter an integer 1-4; 0 to Exit\n");

scanf("%d",&n_term);

switch (n_term){

case '1':

printf("\n1 term approximation\n");

y2 = x;

printf("Approximate log(1+x) = %.5f",y2);

break;

case '2':

printf("\n2 term approximation\n");

y2 = x - (pow(x,2)/2);

printf("Approximate log(1+x) = %.5f",y2);

break;

case '3':

printf("\n2 term approximation\n");

y2 = x - (pow(x,2)/2) + (pow(x,3)/3);

break;

printf("Approximate log(1+x) = %.5f",y2);

case '4':

y2 = x - (pow(x,2)/2) + (pow(x,3)/3) - (pow(x,4)/4);

break;

case '0':

break;

default:

printf("unrecognized operator");

break;

}

}

while (n_term != 0);

scanf("%lf",&x);

}