Thread: File output location specification...

Originally Posted by hebali

What?
Sorry, new to this...

Code:

int main(void)
{
  char path[MAX_PATH];
  FILE *db;
 
  get_user_file_path(path, sizeof(path), "root");
 
  db = fopen(path, "w");
  
  ...
 
  fclose(db);
  return 0;
}

Yes, I guess so.
But I didn't understand the formatting of Master's example.
Sorry

The only formatting flag I had in there was a single %s. Which simply places a string. I used snprintf() so that one can avoid buffer overflow.

snprintf([string], [size of the string], [format], ...)

in trying to compile

Code:

size_t get_user_file_path(char *buffer, size_t size, const char *user)
{
  return snprintf(buffer, size, "/%s/Desktop/database.txt", user);
}

I get error "nested functions are disabled, use -fnested-functions to re-enable"
what does this mean?

Don't make a nested function, silly. Put it outside of main.

What is that function:

Code:

size_t get_user_file_path(char *buffer, size_t size, const char *user)
{
  return snprintf(buffer, size, "/%s/Desktop/database.txt", user);
}

It doesn't take user input...

It is assumed, by this function, that you have already gotten the input and it will be passed in as the third parameter.

So why call it?

Originally Posted by hebali

So why call it?

Because you said you wanted the user to be able to specify what directory the file should be written to.

Sorry, I just caught onto what that element is for...
I was assuming I would supply my own string getting function, but then you handed me the above code, with which I was unfamiliar, and I thought this was a better way to get it...
But now I understand what it does...

Thanks for your help

If my example is not suitable for exactly what you are doing be less general and tell me exactly what it is you want.

The only different way of doing this would be:

Example:

Code:

char buffer[MAX_PATH] = "/"

strncat(buffer, user, MAX_PATH);
strncat(buffer, "/Desktop/database.txt", MAX_PATH);

But that is more lines of code... *shrug*