Can some 1 debug this for me and help me print the output

Ok so heres the deal. I need the program to print in two columns, one with the number of quizzes two wit the grade from each quiz, and then at the end i need the average to print, here is the code so far

Code:

int main()
{
	//Define Varibles int and floats
	int gone,gtwo,gthree,gfour,gfive,gsix,gseven,geight,gnine,gten,k,avg,sum;
	
	
	
	//User Input
	printf("Please enter the 10 grades, make sure you space and use commas to differentiate each grade");
	scanf("%i,%i,%i,%i,%i,%i,%i,%i,%i,%i",&gone,&gtwo,&gthree,&gfour,&gfive,&gsix,&gseven,&geight,&gnine,&gten);
	
	
	
	//Check Input
	if (gone == -gone||gtwo == -1||gthree == -gthree||gfour == -gfour||gfive == -gfive||gsix == -gsix||gseven == -gseven||geight == -geight||gnine == -gnine||gten == -gten)
	
		printf("Please enter a positive grade. Grades can not be negative");
	
	
	else 
	{ 
		sum = gone+gtwo+gthree+gfour+gfive+gsix+gseven+geight+gnine+gten;
		
		avg = sum/10;
	{
		
	
		while(k <=10)
		{
			k++;
			printf("%i,%i",k,avg);
			
		}

	return 0;
	
}

1. gone==-gone does not check to see if gone is negative, it checks (in a very roundabout way) to see if gone is zero.
2. If you intend to use a for loop to print your quiz scores, your quiz scores must be in an array.

i dont think my prof wants arrays but i think it would be best if i use it also im tryin 2 say if the number enter is negative then dont do the else...is there a general way i can say that??

If your prof didn't want arrays, he wouldn't have given the assignment.

That's what if means -- do either or the other, but not both. So put everything you don't want done in the negative case in the else clause of your if-statement.

makes total sense now thanks,im going 2 rewrite n get bck 2 u

> # gone==-gone does not check to see if gone is negative, it checks (in a very roundabout way) to see if gone is zero.
Unless you happen to be using a 1's complement machine, in which case it means something else

It's not ~, it's -. I fail to see how using a one's complement machine will change the rules of mathematics.

Originally Posted by tabstop

I fail to see how using a one's complement machine will change the rules of mathematics.

Possibly because there are two representations for zero in one's complement arithmetic, hence +0 != -0. Then again, I have never had the chance to actually use an implementation that uses one's complement.

+0 and -0 have separate representations, so I don't see how they would compare equal.

Oh, better yet, in section 6.2.6.2, C99 says that "it is unspecified whether these cases actually generate a negative zero or a normal zero, and whether a negative zero becomes a normal zero when stored in an object." Here, "these cases" refer to the use of certain operators like unary + and unary - which may generate a negative zero if the implementation supports negative zeros.

Consequently, whether +0 != -0 in one's complement in a C program is implementation defined.

I apologize; I thought the standard required positive zero and negative zero to compare equal, but I see now that it only permits it.

ok im having problems again this is wut the hw says: Design a program in C which will compute the total grade as well as the average grade received by a student for 10 quizzes. Each quiz grade is out of 10 points. When the program is executed, the user will be asked to input the 10 grades in succession. The output is in the form of a tabular display on the monitor which consists of two columns, one for Quiz # and the other for Quiz Grade. The total and average grade values are to be printed below the table.

where the hell do i put the arrays if its coming as a user input

heres the new code

Code:

int main()
{
	//Define Varibles int and floats
	int gone,gtwo,gthree,gfour,gfive,gsix,gseven,geight,gnine,gten,counter,avg,sum;
	
	
	
	//User Input
	printf("Please enter the 10 grades, make sure you space and use commas to differentiate each grade  ");
	scanf("%i,%i,%i,%i,%i,%i,%i,%i,%i,%i",&gone,&gtwo,&gthree,&gfour,&gfive,&gsix,&gseven,&geight,&gnine,&gten);
	
	
	
	//Check Input
	if (gone >= 0||gtwo >= 0||gthree >= 0||gfour >= 0||gfive >= 0||gsix >= 0||gseven >= 0||geight >= 0||gnine >= 0||gten >=0)
	{
		sum = gone+gtwo+gthree+gfour+gfive+gsix+gseven+geight+gnine+gten;
		avg = sum/10;
	
		
		for(counter=1; counter <=10; counter++)
			{
			counter = counter;
			printf("%i\t%i\n",counter,gone,gtwo,gthree,gfour,gfive,gsix,gseven,geight,gnine,gten);
			}
	}
	else 
	{
		printf("Please enter a positive grade. Grades can not be negative");
		
	}
	
	printf("%i\t%i\t%i",counter,avg,sum);
	
	getch();
	

	return 0;
}

but i need my program to loop and the output to look like this
number of quizzes quiz grade
1 80
2 82
3 50
4 90
5 78
6 90
7 100
8 35
9 11
10 65

can any 1 help me wit my output??

It would REALLY help your case if you used arrays instead of individual variables. However, we can do both, I suppose:

Code:

int *ptrArr[] = { &gone,&gtwo,&gthree,&gfour,&gfive,&gsix,&gseven,&geight,&gnine,&gten };
int i;

...
for(i = 0; i < sizeof(ptrArr)/sizeof(ptrArr[0]); i++)
{
   printf("%d\t\%d\n", i, *ptrArr[i]);
}

There, problem solved.

[Of course, your professor will know immediately that you didn't come up with this yourself, at least if he asks you to explain what the code does, so you are probably better off working out how to solve it yourself].

--
Mats

--
Mats