I wanted it to print the whole matrix, though, not just a single element. I tried doing printf("%d", mat[row][col]), but that didn't work...it gave me that big number I was telling you about earlier. Is this wrong? If so, what would be the correct way to print the whole matrix?
Wait -- did you print out all 25 numbers without any spaces between them?
No, I'd enter them with spaces between them, like 1 2 3 4 5 etc.
So? Show the actual code that you used to print them out.
Here's what happens when I run the program:Code:#include <stdio.h> #include <stdlib.h> #define DIM 5 int main() { int mat[DIM][DIM] = {0}, row, col, rowSum, colSum; printf("Enter 25 numbers: "); for (row = 0; row < DIM; row++) for (col = 0; col < DIM; col++) scanf("%d", &mat[row][col]); printf("\n%d\n", mat[row][col]); rowSum += mat[row]; colSum += mat[col]; printf("The sum of the rows is: %d", rowSum); printf("\n"); printf("The sum of the colums is: %d", colSum); return 0; }
Enter 25 numbers: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
25
2621304
The sum of the rows is: -594119456
The sum of the colums is: 13106020
Process returned 0 (0x0) execution time : 14.185 s
Press any key to continue.
2621304 is supposed to be the matrix. Ignore the sums; I know they're wrong.
At the end of the for loop, both row and col have been incremented past legal subscripts. You have to put the print statement inside a double-for loop, because it's not as though going through an array and printing it differs from going through an array and reading it in in any way whatsoever.
Like I explained a week ago, you have a pair of for loops to read the data in.
Now use a pair of for loops to scan all the elements of the array. Then figure out at which point where
sumOfSomething[row] += mat[row][col];
would be a good place.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Take a look at this, it may help you out a bit
Code:#include <stdio.h> #include <stdlib.h> #define N 5 int main(void) { int i,j,k=1,row_tot,col_tot; int a[N][N]; //initialising the matrix for(i=0;i<N;i++) for(j=0;j<N;j++) a[i][j]=k++; //printing matrix and calculating row totals for(i=0;i<N;i++) { row_tot=0; for(j=0;j<N;j++) { printf("%3d ",a[i][j]); row_tot+=a[i][j]; } printf("|| %d ",row_tot); printf("\n\n"); } printf("==========================\n"); for(i=0;i<N;i++) { col_tot=0; for(j=0;j<N;j++) col_tot+=a[j][i]; printf("%3d ",col_tot); } printf("\n\n"); system("PAUSE"); return 0; }
Last edited by chottachatri; 10-29-2008 at 05:38 AM.
s/bit/totally
You could have at least left a bit of mystery for the OP to work on.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Okay, a put a printf in the nested for loop, but instead of printing the 5x5 matrix, it just prints all 25 numbers right in a row. How do I fix this?
Code:#include <stdio.h> #include <stdlib.h> #define DIM 5 int main() { int mat[DIM][DIM] = {0}, row, col, rowSum, colSum; printf("Enter 25 numbers: "); for (row = 0; row < DIM; ++row) { for (col = 0; col < DIM; ++col) { scanf("%d", &mat[row][col]); printf("%d ", mat[row][col]); } } rowSum += mat[row][col]; colSum += mat[row][col]; printf("The sum of the rows is: %d", rowSum); printf("\n"); printf("The sum of the colums is: %d", colSum); return 0; }
If you want a new line, you have to print it.
