A tricky macro

Ok itz atleast tricky to me!

I want to write a macro which will do something
like

#define PRINTF(x) printf x

:
somewhere in code
:
PRINTF(("This is a zero %d\n", 0));
:
:

Works fine until now.

Now I need to make it something like

#define PRINTFX(x) \
fnCall(someparam, x)

Cant get this to work! Please note that x denotes variable number of parameters like printf.

The intended use is like
PRINTFX("One", "This is one %d\n", 1);
PRINTFX("Two", "Nothing);

Can add any number of paranthesis to the parameters.

Thanks for any help, nope this is not a brain teaser, it would be cool if I could make this work ... else the good old way, multiple functions with variable number of parameters to a function.

i don't think it's possible with #defines. printf is a weird function, though. it doesn't use multiple prototypes.
http://www.purdue.edu/PUCC/Short-Cou...s/p_00930.html
this should help answer questions

Edit: i read your post again and realized you knew this already. i don't think it's possible with #define. can't overload a define, nor can you just put it all in parenthesis without causing problems.

This might work for you, but you still have to use the (()) trick for all the additional parameters

Code:

#include <stdio.h>
#include <stdarg.h>

#define PRINTFX(x,y) \
    fnCall( x, magic y ) 

void fnCall ( char *x, char *y ) {
  printf( "%s %s\n", x, y );
}
char *magic ( const char *fmt, ... ) {
  static char buff[BUFSIZ]; // must be static
  va_list   ap;
  va_start ( ap, fmt );
  vsprintf ( buff, fmt, ap );
  va_end ( ap );
  return buff;
}

int main ( ) {
  PRINTFX( "One", ("This is one %d\n",1) ); 
  PRINTFX( "Two", ("Nothing") ); 
  return 0;
}

Thanks! That worked. Sorry I was tardy in getting back to the list.