pointer/ array question..

This is a discussion on pointer/ array question.. within the C Programming forums, part of the General Programming Boards category; Code: printf("%p\n", array); i know that unlike other variables when we want to do some operation on an array it ...

  1. #1
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    pointer/ array question..

    Code:
    printf("%p\n", array);
    i know that unlike other variables
    when we want to do some operation on an array
    it uses the physical address of the array

    but there are many cells in the array
    does it prints every one of them??

    does the array always defined as pointer ??
    even if we make every cell as int
    Last edited by transgalactic2; 10-14-2008 at 05:55 AM.

  2. #2
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    The compiler will pass an array as a pointer to the first element when passing it to a function. In this case, the function is printf, but it makes no difference to how the array is passed. It will show you the address of the first element of the array.

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  3. #3
    Woof, woof! zacs7's Avatar
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    > does it prints every one of them??
    Try it for yourself... that'd be a no

    > does the array always defined as pointer ?? even if we make every cell as int
    Yes. But you should be casting to (void *) as "%p" requires (which may be implicit, but being explicit is always good).

  4. #4
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    Huh?

    Because printf() allows a variable-number-of-arguments, I don't think the user's variable types can be checked against some expected prototype. Somewhere it is said that a pointer is a pointer is a pointer (its footprint, not "pointer arithmetic"), so stacking pointers to the printf() function will be safe, and always syntactically error free.

  5. #5
    and the Hat of Guessing tabstop's Avatar
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    I don't think it's a size issue; it's just that %p prints "void *". It's not guaranteed to print anything else. Of course it does, for the reasons you mentioned.

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