array and for loops

[retrosciene]

The problem is as follows, Write a program to read in an array containing the co-efficients of the polynomial and compute the value of the polynomial for a given value of x.

e.g :By Horners method 3+4x+5x^2+6x^3+7x^4 can be written as;
3+(4+(5+(6+7x)x)x)x
In my understanding this is like;

a = 6+7x
b = 5+ ax
c = 4+ bx
d= 3+cx
where 6 = a(n-1), 7 = a(nx), 5 =a(n-2) , 4 =(a n-3) etc

this is my code so far and i really really am lost as to where to go from here and finish the code.

this is my code so far and i really really am lost as to where to go from here and finish the code.-----------------------------------------------------------------------------------------------------
CODE
------------------------------------------------------------------------------------------------------

#include<stdio.h>
#include<math.h>
#define MAX_SIZE 50

void main (void);

void main(void)
{

int n,i;
double coeffs[MAX_SIZE],x,result;

printf("enter order of equation");
scanf("%d",&n);

printf("enter the value of x/n");
scanf("%lf",&x);
                                      
                          for(i=n-1;i>=0; i--)
                          {
                                 printf("enter coeffs[%d]:", i+1);
                                 scanf("lf%",&coeffs[i]);
                          }
                                 result =(x*coeffs[i]);
                                 printf("the array elements are %d,coeffs[i]);

                                   for(i=n-1;i>=0;i--)
                                   {
                                       n+(n-1)x
                                   }

[anon]

1) It's int main(void), and I don't think you need a prototype for that.

2)

scanf("lf%",&coeffs[i]);

The %-symbol must come before the control characters.

3)

printf("the array elements are %d,coeffs[i]);

Missing a terminating ", and the format character is wrong (%f for doubles).

4)

n+(n-1)x

C (and I think programming languages in general) don't support shorthands in mathematical notation. If you mean multiplication, you have to use the * operator at the right place.

Also it looks like this line would have no side-effects since you don't assign the result to anything (doesn't change anything should you leave it out altogether).

In general, don't try to write the whole program at once without testing it. Compile (and test what you have this far) more often, even after adding each line.

[retrosciene]

yes you are right about my syntax errors, but have you any idea of how to actually the code to solve the problem should look like?

[anon]

Do you mean that the coefficents should be input by the user and stored in the array, so you'd have an array containing [3, 4, 5, 6, 7] and a variable x, e.g 3.4?

In pseudocode this shouldn't be all that difficult:

get coefficents from user
get x from user
result = 0.0
power_of_x = 1.0 //x ^ 0
for each coefficent
     result += coefficent * power_of_x
     power_of_x *= x //next power of x
output result

Or you might also use the pow() function from <math.h>.