Problem of declaration.

This is a discussion on Problem of declaration. within the C Programming forums, part of the General Programming Boards category; Hi!! I've trying to implement this function: Code: void display(account *x,FILE *ptr){ account temp; strcpy(temp.user_name , "doesn't exist."); strcpy(temp.password , ...

  1. #1
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    Problem of declaration.

    Hi!!
    I've trying to implement this function:
    Code:
    void display(account *x,FILE *ptr){
                                account temp;
                                strcpy(temp.user_name , "doesn't exist.");
                                strcpy(temp.password , "Doesn't exist.");
                                temp.privilige = 4;
                                int i = 0;
                                while(!feof(ptr)){
                                                  fread(&temp,sizeof(account),1,ptr);
                                                  if(!strcmp(temp.user_name , x.user_name)){
                                                                                            temp = *x;
                                                                                            exit(1);
                                                                                            }
                                                  }
                                                  printf("\tThe name is: %s\n",temp.user_name);
                                                  printf("\tThe password is: %s\n",temp.password);
                                                  switch(temp.privilige){
                                                                         case 1 :
                                                                              printf("\tThe privilige is admin.\n");
                                                                              break;
                                                                         case 2:
                                                                              printf("\tThe privilige is: general\n");
                                                                              break;
                                                                         case 3:
                                                                              printf("\tThe privilige is mail-only.\n");
                                                                              break;
                                                                         default :
                                                                                 printf("Doesn't exist.\n");
                                                                         }
                                                                         exit(1);
                                                  
                                                  
                              }
         }
    Why the compilter says "user_name" undeclared in the first strcmp call??
    I didn't finish debugging it so..it is full of problems I guess!

  2. #2
    and the Hat of Guessing tabstop's Avatar
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    The easy guess is that the struct account doesn't contain a field called user_name.

  3. #3
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    Well, it does!
    Code:
    typedef struct{
                   char user_name[MAX2],password[MAX2];
                   int privilige;
            }account;
    or Am I missing something?

  4. #4
    and the Hat of Guessing tabstop's Avatar
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    If that typedef is visible to the compiler (in a header file?), then you didn't get the error user_name undeclared. If you did get that error, then the typedef isn't visible.

  5. #5
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    It was declared as a global variable, I guess that is equivalent to being in a header file. the problem still persists.

  6. #6
    and the Hat of Guessing tabstop's Avatar
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    Alright I misread strcpy for strcmp. I was going to spring this on you later when you got there, but we're here now: the thing on the left side of . must be an actual thing. If it is a pointer, well, that doesn't work. Fortunately, the C gods have given us -> which does the same thing, but the left side is a pointer. So you can't ever do x., you must do x-> .

  7. #7
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    JUst to make things clearer for you, you can easily notice that an "}" is added. when I remove it, a lot of similar problems with other variables of type x.user_name arise in the same manner.
    Don't what is going on really!!

  8. #8
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    Ok that worked for that one.
    but for this is didn't:
    That is a simple sorting.
    Code:
    void sort(account x[],int n){
                           int result;
                           int min;
                           for (int i = 0 ; i < n  - 1 ; i++){
                                 min = i;
                                 for (int j = i + 1 ; j < n; j++){
                                          if ((result = strcmp(x[i].use_name,x[j].user_name)) > 0)  (here I'm having problems)
                                                      min = j;
                                          }
                                 account temp;
                                 temp = x[i];
                                 x[i] = x[min];
                                 x[min] = temp;
                                 }
         }

  9. #9
    and the Hat of Guessing tabstop's Avatar
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    Quote Originally Posted by Leojeen View Post
    Ok that worked for that one.
    but for this is didn't:
    That is a simple sorting.
    Code:
    void sort(account x[],int n){
                           int result;
                           int min;
                           for (int i = 0 ; i < n  - 1 ; i++){
                                 min = i;
                                 for (int j = i + 1 ; j < n; j++){
                                          if ((result = strcmp(x[i].use_name,x[j].user_name)) > 0)  (here I'm having problems)
                                                      min = j;
                                          }
                                 account temp;
                                 temp = x[i];
                                 x[i] = x[min];
                                 x[min] = temp;
                                 }
         }
    You should use intellisense or something to keep you from typing "use_name" instead of "user_name".

  10. #10
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    Ya ya sorry,
    It is 5am here, I'm awfully tired that's why!
    last thing! what does this mean:
    [Warning] unreachable code at beginning of switch statement .
    Thank you

  11. #11
    and the Hat of Guessing tabstop's Avatar
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    Quote Originally Posted by Leojeen View Post
    Ya ya sorry,
    It is 5am here, I'm awfully tired that's why!
    last thing! what does this mean:
    [Warning] unreachable code at beginning of switch statement .
    Thank you
    Anything between the switch and the first case label is guaranteed to never happen.

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