Array of pointers help

OK I am having problems understanding how to get started on a program so if someone could try and explain this to me adn start me off or give me a clue or something it would be helpful. Im not a cse major and so its kind of fuzzy to me.

For this assignment, assume experiment X has been run 3 times, and that each
run produced 15 results, and each result is treated as an integer. So the data
structure of choice will be an array of 3 pointers, each of which points to one
of the arrays of 15 results of a given run of the experiment.

Declare the array of pointers in main() and initialize each element to
0 (zero). Then, for each element of the array of pointers, allocate memory
for an array of 15 integers and initialize each element to the value -1.

Then set up and call a function to store data from the user into the
arrays of 15 integers. For this assignment, prompt for 3 integers
at a time, with each of the 3 integers going into it's own array of 15
integers, at the next available index, for a total of 15 prompts. For
purposes of this assignment, and for help in debugging, print out the
contents of each array as a new number is added. All numbers to be
entered by the user are in the range 0 .. 9.

I disagree. I think the data structure of choice would be a two dimensional array [15][3], with a pointer to [0][1], [0][2], and [0][3].

Although it's effectively the same thing, strategy b gets my vote as you're dealing with static arrays of a known size.

We have to do it the way its stated on my message though so thats the problem. How would i start it?

> Declare the array of pointers in main() and initialize each element to
> 0 (zero). Then, for each element of the array of pointers, allocate memory
> for an array of 15 integers and initialize each element to the value -1.
I'll show you the declaration and malloc

Code:

#include <stdlib.h>

int main ( ) {
   int *arr[3];

   // pointless exercise given the following malloc calls
   for ( i = 0 ; i < 3 ; i++ ) arr[i] = 0;  // same as NULL

   // 15 ints for each one
   for ( i = 0 ; i < 3 ; i++ ) arr[i] = malloc( 15 * sizeof(int) );

   for ( i = 0 ; i < 3 ; i++ ) {
      for ( j = 0 ; j < 15 ; j++ ) {
         arr[i][j] = -1;
      }
   }

   // now free the memory
  
   // and finally...
   return 0;
}

thank you for the help. Can i now begin with the rest of the program though?

My code is not working I keep getting all types of errors can someone please help me.

Help!!
here is the code:

#include <stdio.h>
#define Size 3


void store_data(int *arr);
void process(int *arr);

int main (void)
{
int *arr[Size],i,j;


for(i=0; i<Size; i++)
arr[i]=0;
for(i=0; i<Size; i++)
arr[i] = (int *) (malloc(15*sizeof(int)));
if(arr == NULL){
printf("Unable to get memory");
return 1;
}
for(i=0; i<Size; i++) {
for(j=0; j<15; j++) {
arr[i][j]=-1;
}
}

store_data(arr);


free( (void *)arr);

return 0;
}

void store_data(int *arr);
{
int i,j;

for(i=0; i<3; i++) {
for(j=0; j<15; j++) {
printf("Enter three integer values: ");
scanf("%d %d %d", arr[i][j], arr[i][j], arr[i][j]);
}
}

}

void process(int *arr)
{
/* not done yet */
}

I've added comments where I believe you should look to find errors.

Code:

// I don't know which compiler you are using, but shouldn't you
// also include stdlib.h or malloc.h?
#include <stdio.h>
#define Size 3 


void store_data(int *arr); 
void process(int *arr); 

int main (void) 
{ 
    int *arr[Size],i,j; 


    for(i=0; i<Size; i++) 
        arr[i]=0; 

    for(i=0; i<Size; i++) 
        arr[i] = (int *) (malloc(15*sizeof(int))); 

// in the following don't you want to check each arr[i] to
// be sure that the memory was allocated?
    if(arr == NULL){
        printf("Unable to get memory");

// if memory was allocated for say, arr[0] and arr[1] but
// not for arr[2], shouldn't you free the memory for
// arr[0] and arr[1] before exiting?
        return 1; 
    } 

    for(i=0; i<Size; i++) { 
        for(j=0; j<15; j++) { 
        arr[i][j]=-1; 
        } 
    } 

    store_data(arr); 


    free( (void *)arr); 

    return 0; 
} 


void store_data(int *arr);  // <--- that  ";" shouldn't be there
{ 
    int i,j; 

// look at the scanf(...) line, aren't you putting
// all three of the integers that the user entered
// into the exact same memory location?
// Read the assignment description again, you should
// do a total of 15 prompts, 3 integers each time, into
// consecutive memory locations
    for(i=0; i<3; i++) { 
        for(j=0; j<15; j++) { 
            printf("Enter three integer values: "); 
            scanf("%d %d %d", arr[i][j], arr[i][j], arr[i][j]); 
        } 
    } 

}

what is teh problem with my function. Everytime i compile on Visual C++ it says that subscript requires array or pointer type one the line of my scanf.

void store_data(int *arr)
{
int i,j;

for(i=0; i<3; i++) {
for(j=0; j<15; j++) {
printf("Enter three integer values: ");
scanf("%d %d %d", arr[i], arr[i], arr[i]);
}
}

}

Code:

#include <stdio.h> 
#include <stdlib.h> //!! needed for malloc/free

#define Size 3 
//!! one for all the 15's as well?

void store_data( int *arr[] ); //!! wrong prototype

int main (void) 
{ 
    int *arr[Size],i,j; 

    for(i=0; i<Size; i++) 
        arr[i]=0; 

    for(i=0; i<Size; i++) {
        arr[i] = malloc( 15 * sizeof(int) ); 
        if ( arr[i] == NULL ) { //!!
            printf("Unable to get memory"); 
            return 1; 
        }
    } 

    for(i=0; i<Size; i++) { 
        for(j=0; j<15; j++) { 
            arr[i][j]=-1; 
        } 
    } 

    store_data(arr); 

    //!! should be free[i] - to mirror the malloc
    //free( arr ); //!! (if you need the cast, you're compiling c++

    return 0; 
} 

void store_data( int *arr[] )
{ 
    int i,j; 

    for(i=0; i<Size; i++) { //!! you defined it, use it!
        for(j=0; j<15; j++) { 
            printf("Enter three integer values: "); 
            scanf("%d %d %d", &arr[i][j], &arr[i][j], &arr[i][j] ); 
        } 
    } 

}