assigning a memory address to a pointer

Normally an address is assigned to a pointer this way:

Code:

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int X, *ptr=&X;

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How can I assign the address from a string literal, Eg.

Code:

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#define addr "0xbfe146bc"
*ptr=addr;  //obviously not

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Such that this will now be the actual address of the pointer and usuable that way normally (if you need to know why, see
http://cboard.cprogramming.com/showthread.php?t=107115

convert it to unsigned long using strtoul
then, cast to pointer of the appropriate type

Quote:

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Originally Posted by vart

convert it to unsigned long using strtoul
then, cast to pointer of the appropriate type

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I presume that's what you were trying to do with your example in the other thread, but it doesn't work!

Quote:

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Originally Posted by MK27

I presume that's what you were trying to do with your example in the other thread, but it doesn't work!

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Works for me

Code:

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#include <stdio.h>
#include <stdlib.h>

int main(void)
{
        char sAddr[] = "0x00ac0098";
        unsigned int uAddr = strtoul(sAddr,NULL,0);
        void* pAddr = (void*) uAddr;

        printf("&#37;p", pAddr);
        return 0;
}

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it prints exactly the same address I have put into the string, of course dereferencing this address will fail - because it is just some random value - low chance to have something available there - put the address of something accessable - and you will have no problem dereferencing it...

Quote:

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Originally Posted by vart

Works for me

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Well, it is also somewhat different than your other code -- but thanks thanks thanks vart, that will do my just fine:)

Why are you even using a string literal for this? I just noticed your other thread was using a string literal too. Why not just make it a constant?

Code:

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#define addr 0x00ac0098

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It is much less overhead.