Hamming Distance?

This is a discussion on Hamming Distance? within the C Programming forums, part of the General Programming Boards category; ive dynamically allocated an array of two bytes using: char *ptr = (char *)malloc (2*sizeof(char)); how can I find the ...

  1. #1
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    Hamming Distance?

    ive dynamically allocated an array of two bytes using:
    char *ptr = (char *)malloc (2*sizeof(char));

    how can I find the Hamming distance between the two bytes?

  2. #2
    The larch
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    Do you mean this?

    I don't see how the allocation of two bytes has anything to do with it...
    I might be wrong.

    Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
    Quoted more than 1000 times (I hope).

  3. #3
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    the example section of that page says:

    The Hamming distance between:

    10 *1* 1 *1* 01 and 10 *0* 1 *0* 01 is 2.

    im trying to find the Hamming Distance between the two bytes in the memory allocated.

  4. #4
    The superhaterodyne twomers's Avatar
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    I'd say you should xor them together, and count the number of 1's from the return of the xoring. To count the number of 1s one solution might be something like... Change this to work for your own situation (note I haven't tested this)

    Code:
    int c, xor_res = thinga^thingb;
    int hamm_dist;
    for( c=1; c; c<<=1 )
      hamm_dist += (xor_res & c );
    
    printf( "Hamming distance between &#37;d and %d, is %d\n", thinga, thingb, hamm_dist );
    Or see the wiki link code. Prolly better and more thought out.

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