Thread: New guy help

All

First thanks for whatever help you can offer. i am trying to finish up a degree is statistics and the powers that be say i have to have a programming class. I am woefully uneducated when it comes to everything besides email and google. So I humbly beg of your help.

My second assignment goes something like this:

write a program to convert test scores from numeric to letter grade

Question one:

what is the best way to do inequalities? I can get "(score >= 90) printf("Grade is A) but I can only use one other inequality because of the left side right side thing.

Question two:

Teacher wants program to loop so user can continue to enter grades. I have the loop set up, but don't know how make the program read y and n for commands to yes repeat or no stop.

Any help that can be offered would be greatly apprecaited. I am currently reading the rules on how to post code.

chip

Code:

/*Define maximum and minimum numeric grade values*/
#define LOW 0
#define HIGH 100
#define YES 1
#define NO 0
#define A 90
#define B 80
#define C 70
#define D 60
#define F 59

int grading (int score);

int main()  {

	int a_score, process, again, intvar;

	again = YES;
	printf("This program will assign a letter grade to a numeric test grade");

	while ( again == YES) {
		/*prompt user and call function to get the test grade, assign returned value to grade in main */
		printf("\n\nPlease enter the numeric test grade.  Grade must be between %d and %d:  ", LOW, HIGH);
		scanf("%d%*c",&a_score);
		process = grading (a_score);
		/*prompt user and call function to determine whether another test grade will be entered*/
		printf("\nWould you like to enter another test grade? y/n");
		scanf("%d%*c", &again);
	}

return 0;

}

int grading (int score)
{

		if (score >= A)
			printf("Grade is A");
		if (score < A)
			printf("Grade is B");

		return YES;

}

int repeat (again)
{

	while (again == 'y' || again == 'Y')
		return YES;
}

[QUOTE=39ster;785323]For question one you need to use else statement in order to only print one result.
QUOTE]

It seems so obvious when someone tells you how to go about it. I tried similar things to that. i just didn't realize the above statements would bound the ones below. Thanks very much for the help.

Chip

Code:

int main()  {

    int a_score, process, again, intvar;

    again = YES;
    printf("This program will assign a letter grade to a numeric test grade");

    while ( again == YES) {
        /*prompt user and call function to get the test grade, assign returned value to grade in main */
        printf("\n\nPlease enter the numeric test grade.  Grade must be between %d and %d:  ", LOW, HIGH);
        scanf("%d%*c",&a_score);
        process = grading (a_score);
        /*prompt user and call function to determine whether another test grade will be entered*/
        printf("\nWould you like to enter another test grade? y/n");
        scanf("%d%*c", &again);
        /* You do not break out of the loop. So you have an infinite loop.
         * Probably because it's a work-in-progress. */
     }

return 0;

}

int repeat (again) /* You do not have a type here */
{

    while (again == 'y' || again == 'Y')
        return YES;
}