use of printf prevents segfault!

This is a discussion on use of printf prevents segfault! within the C Programming forums, part of the General Programming Boards category; gcc 4.1.2 for i386-redhat-linux What I really should have been doing all along, as laserlight eventually points out in another ...

  1. #31
    spurious conceit MK27's Avatar
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    gcc 4.1.2 for i386-redhat-linux

    What I really should have been doing all along, as laserlight eventually points out in another thread, was this
    Code:
    struct thestruct {
    [...]
    } *ray;
    int main () {
         short int nofl, i;
         [...determine nofl]
         ray = malloc(nofl * sizeof(*ray));
         for (i=0; i<nofl; i++) {
              ray[i].member = whatever;
         }
    Sorry for wasting so much time...like I said, bullheaded and new to C. But I did pick up some stuff along the way.
    C programming resources:
    GNU C Function and Macro Index -- glibc reference manual
    The C Book -- nice online learner guide
    Current ISO draft standard
    CCAN -- new CPAN like open source library repository
    3 (different) GNU debugger tutorials: #1 -- #2 -- #3
    cpwiki -- our wiki on sourceforge

  2. #32
    C++ Witch laserlight's Avatar
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    Incidentally, must ray really be a global variable? If feasible, make it a local variable. Also, remember to free() what you malloc(), and to check that malloc() does not return NULL before using ray as a dynamically allocated array.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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