use of printf prevents segfault!

MK27 · 08-27-2008, 12:36 PM

gcc 4.1.2 for i386-redhat-linux

What I really should have been doing all along, as laserlight eventually points out in another thread, was this

Code:

struct thestruct {
[...]
} *ray;
int main () {
     short int nofl, i;
     [...determine nofl]
     ray = malloc(nofl * sizeof(*ray));
     for (i=0; i<nofl; i++) {
          ray[i].member = whatever;
     }

Sorry for wasting so much time...like I said, bullheaded and new to C. But I did pick up some stuff along the way.

**laserlight** · 08-27-2008, 12:38 PM

Incidentally, must ray really be a global variable? If feasible, make it a local variable. Also, remember to free() what you malloc(), and to check that malloc() does not return NULL before using ray as a dynamically allocated array.

08-27-2008, 12:36 PM	#31
MK27 subminimalist Join Date: Jul 2008 Location: NYC Posts: 3,944	gcc 4.1.2 for i386-redhat-linux What I really should have been doing all along, as laserlight eventually points out in another thread, was this Code: struct thestruct { [...] } ray; int main () { short int nofl, i; [...determine nofl] ray = malloc(nofl sizeof(ray)); for (i=0; i<nofl; i++) { ray[i].member = whatever; } Sorry for wasting so much time...like I said, bullheaded and new to C. But I did pick up some stuff along the way. __________________ Accuracy and integrity mean nothing if you don't make it past the censors...*PYTHAGORAS
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08-27-2008, 12:38 PM	#32
laserlight C++ Witch Join Date: Oct 2003 Location: Singapore Posts: 10,364	Incidentally, must ray really be a global variable? If feasible, make it a local variable. Also, remember to free() what you malloc(), and to check that malloc() does not return NULL before using ray as a dynamically allocated array. __________________ C + C++ Compiler: MinGW port of GCC Build + Version Control System: SCons + Bazaar Look up a C/C++ Reference and learn How To Ask Questions The Smart Way
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