Thread: Whats wrong?

Hello, i cant find anything wrong with it, but it isnt working correctly:

Code:

#include <stdio.h>

/*count digits, white space, others */

main() {
	int c, i, nwhite, nother;
	int ndigit [10];
	
	nwhite = nother = 0;
	for(i = 0; i < 10; ++i){
		ndigit[i] = 0;
	}
	while((c = getchar()) != EOF){
		if(c >= '0' && c <= '9'){
			++ndigit[c-'0'];
		}
		else if(c == ' ' || c == '\n' || c == '\t') {
			++nwhite;
		}
		else{
			++nother;
	 	}
 	}
	 	printf("digits =");
	 	for(i = 0; i < 10; ++i) {
		 	printf(" %d", ndigit[i]);
		 	printf(", white space = %d, other = %d\n", nwhite, nother);
	 	}
 	}

It compiles with no errors, but when i run it in cygwin, it is just like a regular input program, it comes up with no output, doesnt say how many words etc ar in it. This is the cygwin command bash:

Code:

Family_2@Family-PC ~
$ cd projects

Family_2@Family-PC ~/projects
$ ls
charcount  count  fahr  helloworld  input  linecount  vnc1l

Family_2@Family-PC ~/projects
$ cd count

Family_2@Family-PC ~/projects/count
$ ls
arrays.cpp  arrays.exe  charcount.cpp  linecount.cpp  wordcount.cpp

Family_2@Family-PC ~/projects/count
$ ./arrays
hello world





WTF?

It won't print anything until it hits eof. Hitting enter just gives it more and more newlines, which it parses before asking for another character

Control-D = eof when inputting via command line

Because the C standard requires every code file to end with a newline character. Obviously, if the program proper is complete, gcc (and pretty much every other compiler, I think) will compile it anyway and just tell you that you forgot that bit.