Hey Guys...
I need to ask for someone to explain the program to wri:
give the program 2 dates
day,mnonth,year
an anozer one
day,month,year
and then it gives the difference....my proble is in one thing....sometimes there are month which are 30,30,28..it differs!! ??
any help
What are your restrictions?
Can it be any year from 2000BC to thousands of years in the future, or are we only concerned with "around now" dates [e.g. 10-20 years in the past until current or a few years ahead of now]. If it is a wide-ranging date, you have to take into account changes in calendars [perhaps] as well as the rather complex math to figure out if a particular year is a leapyear or not [and I don't really know WHAT happens before leap-years came into account].
What library functions, if any, are you allowed to use?
For example, can you use standard C time functions (e.g. difftime)?
Do you want the difference in years, months, days, or just as number of days between two dates.
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
Forgive me that the below data validator is in c++ but this may point you in the right direction
HOW TO MAKE DATE VALIDATOR PROGRAM IN C++
http://www.cplusplus.com/forum/general/3094/
How about running thorough each month in the current year and using an if statement to get the length? Also remember to check for leap year in feburary.sometimes there are month which are 30,30,28..it differs!!
Well..I want the just the number of days in between the two dates..but,I will check difftime
Thanks everyone
Thanks BobSO327...and by the way difftime is for seconds !! not days
thanks anyways
Do you think it would be possible to convert seconds to days?Originally Posted by DaniiChris
Thanks BobSO327...and by the way difftime is for seconds !! not days
thanks anyways
[Hint: 15180h]
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
You can derive the days from it tho: days = seconds / xxxx
Last edited by mike_g; 08-18-2008 at 07:04 AM.
Argh. Let 'em hang for a bit before giving the answer directly... ;-) The memory of having to calculate it/come up with it will stay much longer than being given it as a "this is the number you need" - unless you have a very good memory and remember those things immediately, it's much better to learn the process of how to calculate it, both for the learning experience as well as to actually have more in the brain to connect to the result.
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
Ok, I'll let him work it out
1. Convert dates into Unix timestamps
2. Subtract timestamps from eachother
3. Convert the result into a date
4. Subtract 1970 from the year number, 1 from month, 1 from day
This way you get the difference using years, months, days, and possibly hours, minutes and seconds.
Last edited by maxorator; 08-18-2008 at 08:23 AM.
