Thread: Palindrome in C

Hello!
Was just wondering if there's a C program which can take from the user a number and it checks if its a palindrome or not...I know that we %10
right ?
May you show it to me!

I could show you a palindrome program but I need to write a paper on the Boston tea party. I know it involves tea. And Boston. Could you write it for me?

Thanks!

Well..if you get into details about what you want me to write..would be my pleasure
as for the palindrome I will do the Macgyver said..I will try first and when I give up I will come in here

My idea was to place the input into an array (easy to do if you can use getchar to collect input). Then just iterate through the array.

If a number has k digits, (which you should know if you've converted it to a string) then compare every digit i to k - i. If they're all equal, you have a palindrome. Not hard.

Thanks everyone! Will post my code as soon as I get it done!
I totally apreiciate every single one in here

I gave it a try! and here it is
Thanks to everyone

Code:

#include <stdio.h>
int main()
{
int x,num,p,rev;
printf("Enter your desired number you want to check");
scanf("%i",&num);

while(num > 0)
	{
	p = num % 10;
	rev = num*10 + p;
	rev = num / 10;
	rev = x;
	}

if (x == rev)
printf("Yes,Its a Palindrome");
else
printf("No,It isn't a Paindrome");
return(0);
}

I came up with this in about 5 minutes. Of course it doesn't work, because I intentionally broke it. May you fix it?

(Code highlighting courtesy of dwks' Codeform!)

Code:

#include <stdio.h>
#include <stdlib.h>

int is_palindrome(int number) {
   int n = abs(number);
   int r = 0;
   
   while (n > 0) {
      r = r + n%10;
      n /= 10;
   }
   
   return r == number;
}

int main(int argc, char **argv) {
   int num;
   
   if (argc > 1)
      sscanf(argv[1], "%d", &num);
   else {
      printf("Enter a number: ");
      fflush(stdout);
      scanf("%d", &num);
   }
   
   printf("%s", is_palindrome(num) ? "YES" : "NO");
   putchar('\n');
   return 0;
}

I still like my way better:

Code:

#include <stdio.h>
#include <string.h>

int palindromicity ( const char * numbuff )
{
    size_t i, len;
    for( i = 0, len = strlen( numbuff ); i < len; i++ ) {
        if( numbuff[i] != numbuff[len - 1 - i] ) return 0;
    }

    return 1;
}

int main ( void )
{
    char numbuff[32];
    printf( "Please enter a integer:\n" );
    fgets( numbuff, sizeof numbuff, stdin );
    numbuff[strcspn( numbuff, "\n" )] = '\0';

    printf( "&#37;s is%s palindromatic.\n", numbuff,
        palindromicity( numbuff ) ? "" : " NOT" );

    return 0;
}

You could verify that the input was a number but it really doesn't have an effect on the program's outcome.