# Thread: any solution to convert given char*(number) to required unsigned char*(hex of number)

1. ## any solution to convert given char*(number) to required unsigned char*(hex of number)

Given For e.g,

Code:
char input[] = "10011210582553796";

now Hexadecimal of 10011210582553796 is 2391249A8B74C4.

So output unsigned char* should have value,
Code:
unsigned char output[8] = {0x00,0x23,0x91,0x24,0x9A,0x8B,0x74,0xC4};
Any solution to convert given input char* to output char* with above mentioned requirement.

code should run on platform for which __int64/signed long long is not supported.

2. You mean convert decimal integers to hex? Yes there is.
Code:
int myNumber = 10;

printf("hex of &#37;d is %X", myNumber, myNumber);
And if that's not what you mean, explain what you're having trouble with. And not "give me teh codez".

http://forums.devshed.com/c-programm...ed-541856.html

Or are you just gonna run from site to site in the hopes of eventually finding someone to feed you the answer without you showing any effort?

4. Hi zacs7,

The number i have given is out of range of int datatype, so can not use printf of or atoi operation which are supported for int datatype. Actually number can be stored in int64 type but system does not support int64 datatype. So i want to convert is to
Code:
unsigned char output[8] = {0,35,145,36,154,139,116,196}  = {0,0x23,0x91,0x24,0x9A,0x8B,0x74,0xC4}
Even i cannot use left shift or right shift (multiplication/devision) when number reaches above integer capacity.

Try not to spam your question everywhere. Do you know how to convert decimal to hex in the first place?

6. found solution...

Code:
int number = 0;
char numberchars[] = "10011210582553796";
int i = 0;
int ans = 0;
int carry = 0;

char remainderArray[100] = {0};
int remindex = 0;
int ansindex = 0;
int remainder = 0;

while( numberchars[i] != '\0' )
{
while( numberchars[i] != '\0' )
{
char currentchar[2] = {0};
currentchar[0]=numberchars[i];

int num = atoi(currentchar);
num += remainder;
remainder = 0;

if ( num < 2  )
{
remainder = num;
if(i>0)
}
else
{
remainder = num % 2;
int answer = num / 2;

char a[2] = {0};

}

i++;
remainder *= 10;
}

char a[2] = {0};
int rval = remainder / 10;
itoa(remainder / 10,a,10);

remainderArray[remindex++] = a[0];
ansindex = 0;
remainder = 0;
i=0;
}

char int64[8] = {0};

for(int k=0;remainderArray[k]!= '\0';k++)
{
int64[7-(k/8)] |= ((remainderArray[k]-'0') << (k%8));
}

7. Have your tested that solution? itoa is not properly defined how have you declaried your 'a' string for the function call?