Help! confused on how to run this program about money

this is sort of like an atm-ish project....
i thought of many possible things i learn't but maybe it still isn't enough...
maybe you can help me finish this program with just basic variables in it.. printf, scanf, and the like...

THE PROBLEM: create a program that will ask an amount in pesos(integer) and determine the lowest # of bills he will need to achieve the amount entered. The bills in use are 1000peso, 500peso, 200peso, 100peso, 50peso, 20peso, 10peso, 5peso, 1peso.
/* peso is a currency XD */

an example would be if i entered an amount of 1898 pesos, it would come up with

you need:
peso1000:1
peso500:1
peso200:1
peso100:1
oeso50:1
peso20:2
peso10:
peso5:1
peso1:3

so far i've made this: i know the nAmnt's in the printf's are wrong but i just don't know what to put.

Code:

#include <stdio.h>
main()
{
	int nPeso1000,
	    nPeso500,
	    nPeso200,
	    nPeso100,
	    nPeso50,
	    nPeso20,
	    nCoin10,
	    nCoin5,
	    nCoin1,
	    n,
	    nAmnt;

	    printf("Enter Amount:");
	    scanf("&#37;d", nAmnt);
	    printf("xxxxxxxxx\n");
	    printf("xxBillsxx\n");
	    printf("xxxxxxxxx\n\n");
	    printf("1000:%d\n",nAmnt);
	    printf("500:%d\n", nAmnt);
	    printf("500:%d\n", nAmnt);
	    printf("200:%d\n", nAmnt);
	    printf("100:%d\n", nAmnt);
	    printf("50:%d\n", nAmnt);
	    printf("20:%d\n\n", nAmnt);
	    printf("xxxxxxxxx\n");
	    printf("xxCoinsxx\n");
	    printf("xxxxxxxxx\n\n");
	    printf("10:%d\n", nAmnt);
	    printf("5:%d\n", nAmnt);
	    printf("1:%d\n", nAmnt);
	    getch();
	    return 0;
 }

1898 / 1000 = 1 <-- this is your first answer
1898 &#37; 1000 = 898 <-- use this as the start for your next answer

Do that all the way down through your currency values.

If you had to count out 1898 pesos yourself, how would you do it? Once you know how to do it, then you can carry those calculations into C.