Thread: Regarding accessing the structure member

Hi,
please see the below code.

Code:

struct kk
{
    char a;
    char name[10];
};


int main()
{
    char* getname(struct kk *,char *);
    struct kk p;
    char *ret = NULL;
    p.a =0;
    strcpy(p.name,"hai");
    ret = getname(&p,"name");
    printf("result : %s",ret);
    return 0;
}


void getname(struct kk *ptr,char *string)
{
    char *result;
    result=(char *)malloc(10);
    strcpy(result,    );--->what can i put?
    printf("%s",result);

}

here getname is a function takes structure pointer, member name as inputs .
purpose of function is to print the value of passed structure member.

in getname function ,

strcpy(result, );------ what can i put here as second argument to access the structure member "name".

is strcpy(result,ptr->string) right one? or strcpy(result,ptr->*string) right one?

i want to print the string result which is equal to "hai".

Could you please help me regarding this?

Thanks in advance,
Srinu.






~

Code:

#include <stdio.h>



struct kk
{
    char a;
    char name[10];
};

char* getname(struct kk*,char*);





int main()
{
    struct kk p;
    char *ret = NULL;
    p.a =0;
    strcpy(p.name,"hai");
    ret = getname(&p,"name");
    printf("result : %s",ret);
    return 0;
}


char* getname(struct kk *ptr,char *string)
{
    char *result;
    result=(char *)malloc(10);
    strcpy(result,ptr->name);
    printf("%s",result);
		return result;

}

Hi vlrk,
in the getname function,you did not use the string pointer that is second argument.
i want a output with the help of second argument.

strcpy(result,ptr->string); or strcpy(result,ptr->*string)..............

Originally Posted by vlrk

Code:

#include <stdio.h>



struct kk
{
    char a;
    char name[10];
};

char* getname(struct kk*,char*);





int main()
{
    struct kk p;
    char *ret = NULL;
    p.a =0;
    strcpy(p.name,"hai");
    ret = getname(&p,"name");
    printf("result : %s",ret);
    return 0;
}


char* getname(struct kk *ptr,char *string)
{
    char *result;
    result=(char *)malloc(10);
    strcpy(result,ptr->name);
    printf("%s",result);
		return result;

}

Originally Posted by Elysia

As vlrk already told you, it's strcpy(result,ptr->string).
Why?
Because ptr is a pointer, and therefore we must dereference it first to access its members. So it becomes
strcpy(result,(*ptr).string)
It's necessary to use parenthesises due to "*" being lower priority than ".".
A shortcut for this syntax is "->".

And let me ask you a question then... why do you need to dereference the member string?

Hi Elysia,
if u use strcpy(result,ptr->string) then u will see error that is

error: âstruct kkâ has no member named âstringâ.