Thread: help me to find the problem

Code:

#include <stdio.h>
#include <conio.h>

void getpass(char*);

int main(){
	char tpass[9];

	printf("\nPlease enter your password:");
	getpass(tpass);
	while (tpass != "password"){
		printf("\n\aWrong password! please try again:");
		getpass(tpass);
	}

}

/***********************************************/
void getpass(char* pass){

	/* function variables */
	char ch;
	int flag = 0, i = 0;

	/* function process*/
	while(flag == 0){
		ch = getch();
		if (ch == '\r'){
			if (i != 0){
				pass[i] = NULL;
				flag = 1;
				continue;
			}
			printf("\a");
			continue;
		}
		else if (ch == '\b'){
			printf("\b");
			i--;
			continue;
		}
		printf("*");
		pass[i] = ch;
		i++;
	}

}

I dont know why it go to while loop when I enter the pass word correctly!

this is a part of my whole code

"password" is a string literal, which is const char*, so you try to compare an array (which becomes char*) to a const char*, which you understand, will never be true, since they are two distinct addresses.
You need to use the strcmp string function for comparing strings in C. Welcome to C.