help me to find the problem

Code:

#include <stdio.h>
#include <conio.h>

void getpass(char*);

int main(){
	char tpass[9];

	printf("\nPlease enter your password:");
	getpass(tpass);
	while (tpass != "password"){
		printf("\n\aWrong password! please try again:");
		getpass(tpass);
	}

}

/***********************************************/
void getpass(char* pass){

	/* function variables */
	char ch;
	int flag = 0, i = 0;

	/* function process*/
	while(flag == 0){
		ch = getch();
		if (ch == '\r'){
			if (i != 0){
				pass[i] = NULL;
				flag = 1;
				continue;
			}
			printf("\a");
			continue;
		}
		else if (ch == '\b'){
			printf("\b");
			i--;
			continue;
		}
		printf("*");
		pass[i] = ch;
		i++;
	}

}

I dont know why it go to while loop when I enter the pass word correctly!

this is a part of my whole code

while (tpass != "password"){

should be

while (strcmp(tpass, "password") != 0){

"password" is a string literal, which is const char*, so you try to compare an array (which becomes char*) to a const char*, which you understand, will never be true, since they are two distinct addresses.
You need to use the strcmp string function for comparing strings in C. Welcome to C.

thanks all