Passing function as argument

This is a discussion on Passing function as argument within the C Programming forums, part of the General Programming Boards category; Originally Posted by Elysia How do you do it? Passing is easy: func(&function); Declaring a function to take a pointer ...

  1. #16
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    Quote Originally Posted by Elysia View Post
    How do you do it? Passing is easy:
    func(&function);

    Declaring a function to take a pointer to a function is less trivial, but something along the lines of:
    typedef return_type (name)(argument_type argument_name);
    void foo(name* pFunction);
    Does that work? I usually see this instead:

    typedef return_type (*name)(argument_type argument_name);
    void foo(name pFunction);
    It is too clear and so it is hard to see.
    A dunce once searched for fire with a lighted lantern.
    Had he known what fire was,
    He could have cooked his rice much sooner.

  2. #17
    C++まいる!Cをこわせ! Elysia's Avatar
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    Yes, both work, but I tend to use the former because it more visible that it is actually a pointer.
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

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