char pointers in C

**Rishi Kumar** · 05-23-2008

thanx Elysia...

i dont get any error with fgets...
i use dev c++ with gcc compiler...
but i get a warning: "passing arg 1 of `fgets' from incompatible pointer type"... y???

**39ster** · 05-23-2008

What's so bad about casting malloc in C? Wouldnt it be better because it will be easier to transfer your C code to C++?

**stevesmithx** · 05-23-2008

Thank you laserlight.
I had saved it as .C
For .c it works.
And I thought extensions are not case sensitive.
Thanks all

**laserlight** · 05-23-2008

What's so bad about casting malloc in C? Wouldnt it be better because it will be easier to transfer your C code to C++?

read casting malloc.

**Elysia** · 05-23-2008

Originally Posted by Rishi Kumar

thanx Elysia...

i dont get any error with fgets...
i use dev c++ with gcc compiler...
but i get a warning: "passing arg 1 of `fgets' from incompatible pointer type"... y???

It means that you are trying to pass an argument to a function that expects a pointer of a certain type, but you are passing another type of pointer.
If we could see the fgets code, maybe we could help.

Example:

Code:

int x;
fgets(&x, 1, 1, f); /* passing arg 1 of `fgets' from incompatible pointer type */

(fgets is expecting char*, not int*)

Originally Posted by 39ster

What's so bad about casting malloc in C?

Because of implicit function calls are masked (in case you forgot to include the header where malloc's prototype resides). See the FAQ for more details.

Originally Posted by 39ster

Wouldnt it be better because it will be easier to transfer your C code to C++?

I certainly do agree with you there. I like to call it C++/C

C code compiled with C++.
But we can't force anyone.

**Rishi Kumar** · 05-23-2008

Code:

#include<stdio.h>
#include<conio.h>
main()
{
char *s[10];
fgets(s, 10, stdin);
printf("&#37;s",s);
getch();
}

it shows a warning...
" passing arg 1 of `fgets' from incompatible pointer type "

i accept only char* as input...

**laserlight** · 05-23-2008

In your new code example, s is an array of 10 char pointers. What you want is:

Code:

#include<stdio.h>

int main()
{
    char s[10];
    fgets(s, 10, stdin);
    printf("&#37;s",s);
    return 0;
}

**Elysia** · 05-23-2008

Try reading the link for implicit main and get rid of it.
The problem is

Code:

char* s[10];

Which creates an array of 10 char pointers.
Thus passing this to fgets will result in char**.
Futher, the array has no allocates storage so you'd get a crash immediately.

And it's better to use getchar() instead of getch() (it's non-standard).

Thread: char pointers in C

Thread Tools

Search Thread

Display

Similar Threads

seg fault at vectornew

Converting a circulating mouse pointer to use a Potentionmeter

newbie needs help with code

Program Crashing

errors in class(urgent )

Tags for this Thread