Help!

Callumagus · 05-20-2008, 03:02 PM

Im new to C Programming, and am attempting to write a program to take the names of ten people and output the highest length. This is what I've got so far:

Code:

#include <stdio.h>

main() {

int Name_Array[10];     /* Creates a variable with 10 indexes */
char Name [10] [25];        /*Creates a char with up to 25 indexes */
gets (Name);
int i=0;

while (i<11)           /* Creates a loop while "i" is less than 11 */

          {

          i=(i+1)
          printf ("\nEnter name", Name_Array[i]);
          scanf (%s, Name [i] [0-25]);

          }

int str_len [10];                   

str_len [1]= strlen (Name_Array [1]);
str_len [2]= strlen (Name_Array [2]);
str_len [3]= strlen (Name_Array [3]);
str_len [4]= strlen (Name_Array [4]);
str_len [5]= strlen (Name_Array [5]);
str_len [6]= strlen (Name_Array [6]);
str_len [7]= strlen (Name_Array [7]);
str_len [8]= strlen (Name_Array [8]);
str_len [9]= strlen (Name_Array [9]);
str_len [10]= strlen (Name_Array [10]);

}

I need to:

a)compress the strlen portion into a few lines
b)get the program to take the str_len array with the highest value and print it....

Thanks!

Adak · 05-20-2008, 03:16 PM

Please edit your post and remove the excess width inside your code tags.

That's called "breaking the forum tables", and genuinely hated, since it's a constant aggravation to scan back and forth to read your post.

Thanks.

You don't need this large an array at all. You need two things: the current name being entered, and the longest name which has been entered, so far.

That's it. Every name that is entered is checked inside the while loop, and if it is longer than the previously longest name, then it replaces it in that role.

swoopy · 05-20-2008, 04:10 PM

Code:

>while (i<11)           /* Creates a loop while "i" is less than 11 */
>
>          {
>
>          i=(i+1)
>          printf ("\nEnter name", Name_Array[i]);
>          scanf (%s, Name [i] [0-25]);
>
>          }

for-loops are nice for this purpose:

Code:

#include <stdio.h>
#include <string.h>
.
.
for (i=0; i<10; i++)           /* Creates a loop while "i" is less than 10 */
{
    printf ("Enter name: ");
    fflush(stdout);
    scanf ("%25s", Name[i]);
}

Now compile, correct any errors, and run. Then add another loop to print out the names. Once you have that working, keep adding code until you have a working program.

05-20-2008, 03:16 PM	#2
Adak Registered User Join Date: Sep 2006 Posts: 2,511	Please edit your post and remove the excess width inside your code tags. That's called "breaking the forum tables", and genuinely hated, since it's a constant aggravation to scan back and forth to read your post. Thanks. You don't need this large an array at all. You need two things: the current name being entered, and the longest name which has been entered, so far. That's it. Every name that is entered is checked inside the while loop, and if it is longer than the previously longest name, then it replaces it in that role. Last edited by Adak; 05-20-2008 at 03:22 PM.
Adak is online now

05-20-2008, 04:10 PM	#3
swoopy Registered User Join Date: Oct 2001 Posts: 2,936	Code: >while (i<11) /* Creates a loop while "i" is less than 11 / > > { > > i=(i+1) > printf ("\nEnter name", Name_Array[i]); > scanf (%s, Name [i] [0-25]); > > } for-loops are nice for this purpose: Code: #include <stdio.h> #include <string.h> . . for (i=0; i<10; i++) / Creates a loop while "i" is less than 10 */ { printf ("Enter name: "); fflush(stdout); scanf ("%25s", Name[i]); } Now compile, correct any errors, and run. Then add another loop to print out the names. Once you have that working, keep adding code until you have a working program. __________________ http://www.freechess.org
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