Thread: Can not find error in this code

I am trying to compare how different functions work and I do not see whats wrong here. I expect to see 100 and 200 on the printf after the second function call and I get 2...2 no matter what I do (changed it from + to *). Can someone look and let me know the problem? Thanks.

Code:

   void swap(int *swapa, int *swapb);
   
   int swap2(int swapa);

   main here....

         int aa = 1;
         int bb = 2;

         /*This works fine*/
         printf("%d is aa before function and %d is bb before function\n",aa, bb);
         swap(&aa, &bb);
         printf("%d is aa after function and %d is bb after function\n",aa, bb);
     
         /*Here is where problem is*/ 
         swap2(aa);
         printf("%d is aa now\n", aa); //
     
         swap2(bb);
         printf("%d is bb now\n", aa);

         functions here...

        void swap(int *swapa, int *swapb)
         { /*params are int* instead of int*/
         int temp;
         temp = *swapa; /* use * to follow the pointer back to the caller's memory*/
         *swapa = *swapb;
         *swapb = temp;
         }
    

         int swap2(int swapa)
         {
         int temp =100;
         int result = swapa + temp;
         return (result);
         }

Thanks I made the correction below:

Code:

          aa = swap2(aa);
          printf("%d is aa now\n", aa);
     
          bb = swap2(bb);
          printf("%d is bb now\n", aa);

and they both = 102 which is confusing because when doing a printf after 1st swap function it reads:

2 is aa now and 1 is bb now

Why are they not 101 and 102?'

Thanks for your help! What a clumsy mistake.