I'm reading the section of my book on Variable Length argument list functions, and I can't quite understand, how the following program averages the numbers. An average is to add the values and to divide by the number of values you added.

Where exactly does function double average( int i, ... ) do this, and how? Please explain.

Code:#include <stdio.h> #include <stdarg.h> double average( int i, ... ); /* prototype */ int main() { double w = 37.5; double x = 22.5; double y = 1.7; double z = 10.2; printf( "%s%.1f\n%s%.1f\n%s%.1f\n%s%.1f\n\n", "w = ", w, "x = ", x, "y = ", y, "z = ", z ); printf( "%s%.3f\n%s%.3f\n%s%.3f\n", "The average of w and x is ", average( 2, w, x ), "The average of w, x, and y is ", average( 3, w, x, y ), "The average of w, x, y, and z is ", average( 4, w, x, y, z ) ); return 0; /* indicates successful termination */ } /* end main */ /* calculate average */ double average( int i, ... ) { double total = 0; /* initialize total */ int j; /* counter for selecting arguments */ va_list ap; /* stores information needed by va_start and va_end */ va_start( ap, i ); /* initializes the va_list object */ /* process variable length argument list */ for ( j = 1; j <= i; j++ ) { total += va_arg( ap, double ); } /* end for */ va_end( ap ); /* clean up variable-length argument list */ return total / i; /* calculate average */ } /* end function average */