pointer char[], help with warning

I'm getting the following error althrough the program is compiling a exe. I've been learning pointers and while playing with integers was fine, adopting the same stragety with a character array of 4, this warning is cropping up.

error: incompatible types in assignment
warning: passing arg 1 of `setAlphaPosition' from incompatible pointer type

function prototype in place.

Code:

void setAlphaPosition(char *alphaPos[4], int x);

declaration is as follows:

Code:

char alphaPosition[4];

calling the function below:

Code:

setAlphaPosition(&alphaPosition, 3);

Code:

void setAlphaPosition(char *alphaPos[4], int x)
{
    /* uses pointer to update string with the 
    alphabetical expression given in regards 
    to position, first, second, third etc .. */
    if ( x == 0 )
        *alphaPos = "1st";
    else if ( x == 1 )
        *alphaPos = "2nd";
    else if ( x == 2 )
        *alphaPos = "3rd";
    else if ( x == 3 )
        *alphaPos = "4th";
    else if ( x == 4 )
        *alphaPos = "5th";
    else if ( x == 5 )
        *alphaPos = "6th";
}

Anyone know what needs adjusting.

Code:

void setAlphaPosition(char alphaPos[4], int x)

Originally Posted by Dave_Sinkula

Code:

void setAlphaPosition(char alphaPos[4], int x)

Adjusting the prototype to reflect your adjustment results in the following:

warning: passing arg 1 of `setAlphaPosition' from incompatible pointer type
top level:
error: conflicting types for 'setAlphaPosition'
error: previous declaration of 'setAlphaPosition' was here
error: conflicting types for 'setAlphaPosition'
error: previous declaration of 'setAlphaPosition' was here

Make up your mind what you're actually trying to send to the function.

Originally Posted by MacGyver

Make up your mind what you're actually trying to send to the function.

I want the memory address of string alphaPosition sent to the function hence why I'm using the & operator before the string when passing the parameter.

Ok he meant to change the whole thing. But I know Todd also didn't notice what you are trying to do.

Example:

Code:

char x[5] = "hi";
strncpy(x, "hi", sizeof(x));