Thread: end of file problems

haoy People...
I've been making this program to identefy a string in a file, and to write down the raws were it appears...
the problem was that when I wrote just

while(!feof(in))

it would read the last raw (string) twice... say I had 6 lines in the text file.. and the string would be in the 6th one..
I would get - line 6 AND line 7 as an output....

it had something to do with EOF cause after changing it to that:

while(fgetc(in)!=EOF)
{
fseek(in,-1,SEEK_CUR);
i++;
fgets(buf,80,in);
if((strstr(buf,str))!=NULL) arr[i]=1;
else arr[i]=0;
}
it read it fine....
can anyone explain why???

sorry about the long thread...

!feof() is buggy, use this instead:

while( fgets( buf, 80, in ) != NULL ) {

-Prelude

Thanks Prelude, I'm still confused though, I know i can use loads of ways to get rid of that, the thing is I want to understand why???
My teacher (not the brightest bulb in the chandellier) says it's because of the O/S... I say that some how the 32 bit (win98) we are using is seeing EOF as 2 Bytes insted of one...

HELP...
O' Wise one....

The reason this happens is because feof() returns the state of the EOF flag. This flag is not set until the EOF has been READ!

Why would you need to read it twice. Once you have read EOF you know the state of the EOF flag so why call feof() and check it again. C'mon use your head!