calling a char *function

This is a discussion on calling a char *function within the C Programming forums, part of the General Programming Boards category; I have a function, char *move(Head head); It has already been declared and the function is created. However, when I ...

  1. #1
    Cogito Ergo Sum
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    calling a char *function

    I have a function, char *move(Head head);

    It has already been declared and the function is created.

    However, when I try calling it from main like:

    move(head);

    It says implicit declaration.

    If I try:

    *move(head); - it gives me an error, likewise for &move(head) - how do I call this type of function?
    =========================================
    Everytime you segfault, you murder some part of the world

  2. #2
    Woof, woof! zacs7's Avatar
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    Have you prototyped it?

    As in, at that point in the program is it declared?

  3. #3
    Cogito Ergo Sum
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    Yes, it's declared in a header file, it's not the only function declared in a header file, so I don't get why it's causing problems.
    =========================================
    Everytime you segfault, you murder some part of the world

  4. #4
    Woof, woof! zacs7's Avatar
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    Code posty time

  5. #5
    Cogito Ergo Sum
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    Hmm I can't post the code unfortunately, it's an assignment =( . I don't want someone copying the code (just incase someone from my class is in here) and then they copy something from me and then when they do a plagiarism test, I may get busted.

    But it looks something like this:



    Code:
    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    typedef struct buffer *EX;
    struct buffer {
      char *buffer;
      EX next;
    };
    
    EX makeNode (void);
    char *move (EX ex);
    
    int main (void) {
      char str[] = "hi, \nmy name is Jude\n";
      int t_len;
    
      t_len = strlen(str);
    
       //do stuff with strings
    
      move(ex);
    
      return  0;
    }
    
    //other functions
    
    char *move (Ex ex) {
      char *buf;
      //stuff
    
      return (buf);
    
      } 
    
    
    EX makeNode(void){
    
      EX node;
      node = (EX)malloc(sizeof(*node));
    
      return (node);
    }
    =========================================
    Everytime you segfault, you murder some part of the world

  6. #6
    a_capitalist_story
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    Spot the difference:

    Code:
    char *move (EX ex);
    char *move (Ex ex)

  7. #7
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    Code:
    char *move (Ex ex) {
      char *buf;
      //stuff
    
      return (buf);
    
      }
    That should be

    Code:
    char * move(EX ex)
    also, you don't declare the 'ex' you are passing to move in main()
    Code:
    >+++++++++[<++++++++>-]<.>+++++++[<++++>-]<+.+++++++..+++.[-]>++++++++[<++++>-] <.>+++++++++++[<++++++++>-]<-.--------.+++.------.--------.[-]>++++++++[<++++>- ]<+.[-]++++++++++.

  8. #8
    Cogito Ergo Sum
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    Quote Originally Posted by rags_to_riches View Post
    Spot the difference:

    Code:
    char *move (EX ex);
    char *move (Ex ex)
    Sorry, that wasn't there in the original code, that was just a typo as I was typing it out here.
    =========================================
    Everytime you segfault, you murder some part of the world

  9. #9
    Cogito Ergo Sum
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    Nvm, I found out what was wrong.

    The original was actually dumpTB

    and I had called it dump, missing the TB, that's why it was implicit. Damn silly mistakes.

    Sorry all
    =========================================
    Everytime you segfault, you murder some part of the world

  10. #10
    Woof, woof! zacs7's Avatar
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    Seriously, I'd avoid 'masking' pointers... unless your assignment says you have to. Kinda hard to follow IMO.

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