initializing structure variables

Given the following code:

Code:

---

#include <stdio.h>
#include <stdlib.h>

typedef struct foo {
  int test;
  char b;
} foo;

int
main(int argc, char *argv[]) {

  foo f = {2, 'c'};
  int i = f->test;
  printf("%d\n", i);

  return 0;
}

---

Why do I get an error when compiling?

test.c: In function 'main':
test.c:13: error: invalid type argument of '->'

When I use decimal notation, such as f.test, it works fine.

a->b is the same as (*a).b - since your f is not a pointer, it is not allowed to use ->, but you should use the "dot" notation (I wouldn't call it "decimal", since that's just one usage of "dot/point").

--
Mats

I think you may have too many "foo"s:

Code:

---

typedef struct foo {
  int test;
  char b;
} foo;

---

Could also be written:

Code:

---

typedef struct {
  int test;
  char b;
} foo;

---

I'm pretty sure that first foo is unnecessary.