sort of stuck

hi all

right now i got this code

if (scanf("%d %d", &year, &month)!=2) {
printf("Input error\n");
}

it sort of behaves how i wanted it to like when i didnt enter 2 integers will pop out input error
however if i enter 1 integer the program will be stuck and just appear normal until i enter something twice

how do i fix it so that it will print input error if i enter less than 2 integer?

thx

One obvious solution, if you expect the user to input all the data on one line is to use a text input, and then "parse" the text input for the relevant data. For example:

Code:

---

char buffer[20];
...
if (fgets(buffer, sizeof buffer, stdin) != NULL || (sscanf(buffer, "%d %d", &year, &month)!=2) {
printf("Input error\n");
}

---

This will make sure that one line of data is input, and then try to translate it to year and month - and if either fails for some reason, it will produce "input error".

--
Mats

thx for the reply mats
but i think this fgets and buffer is way too complicated for this program (we are only allowed to use what we learn)
are there any other simpler methods?

Issue two scanf()'s, one for year, and the second for month.

thx for th reply todd but i dunno y it still doesnt work... if i enter a year but no month like XXXX -
(- means nothing) program wont appear normal until i enter something
the output of program will be like this
Enter year and month: 2008


1<---- random thing on keyboard
twenty hundred eight
has three hundred and sixty six (366) days
January has 31 days

Code:

---

if (scanf("%d", &year)!=1) {
printf("Input error\n");
}

if (scanf("%d", &month)!=1) {
printf("Input error\n");
}

---

So, if you use fgets(), it will read a line. It's not very complicated really, and there is no other (simple) solution that works.

--
Mats