Hex

This is a discussion on Hex within the C Programming forums, part of the General Programming Boards category; I am trying to get the program to print the address in hex numbers ex. 0X2000. What can I do ...

  1. #1
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    Hex

    I am trying to get the program to print the address in hex numbers ex. 0X2000.
    What can I do to get my program to print it like that.
    Code:
    #include<stdlib.h>
    #include<stdio.h>
    
    void cube(double*);
    
    
    main(){
    	
    	double variable=3.43;
    	int* pVariable;
    	
    	
    	printf("Value of variable is %.2lf\n",variable);
    	printf("Address of variable is %p\n",&variable);
    	
    	pVariable=&variable;
    	cube(&variable);
    
    	printf ("New value for variable is %lf\n",variable);
    	
    
    	
    	system("Pause");
    }
    
    void cube(double* pVariable){
    	printf("The number %.2lf\n",*pVariable);
    	*pVariable=*pVariable * *pVariable * *pVariable;
    	printf("The address of pVariable is %p\n",pVariable);
    }

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    printf("0x&#37;08X", 1024);

    Change 8 to whatever length you want it to be
    Last edited by 39ster; 04-01-2008 at 10:38 PM.

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    how do i get the program to do that??

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    Code:
    void cube(double* pVariable){
    	printf("The number &#37;.2lf\n",*pVariable);
    	*pVariable=*pVariable * *pVariable * *pVariable;
    	printf("The address of pVariable is 0x%08X\n",pVariable);
    }
    8 should be enough for a 32 bit value. 16 for 64 bit addresses.
    Last edited by 39ster; 04-01-2008 at 10:45 PM.

  5. #5
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    isnt that actually me inputing the value?
    How do I get the program to find the location and print it by itself? using *int and pVariable.

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    Just replace the cube function with the one i wrote.

  7. #7
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    its not working its giving em errors on this line
    printf("The address of pVariable is "0x&#37;08X"\n",pVariable);

  8. #8
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    The problem I see is that the standard (C99, at least) specifies that &#37;p is the format specifier for pointers, and you have to cast the pointer to void*.

    On the other hand, it is likely that %p will cause the address to be printed in hex, though that is not guaranteed.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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    Sorry, try now. (I edited my post)

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    i just tried that and its giving em errors.
    what do i do to make sure it prints hex

  11. #11
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    According to laserlight you can do this:
    Code:
    void cube(double* pVariable){
    	printf("The number &#37;.2lf\n",*pVariable);
    	*pVariable=*pVariable * *pVariable * *pVariable;
    	printf("The address of pVariable is 0x%p\n",pVariable);
    }
    Btw why dont you tell us the errors?

  12. #12
    C++ Witch laserlight's Avatar
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    what do i do to make sure it prints hex
    In the first place, are you sure it does not print in hex? Try:
    Code:
    #include <stdio.h>
    
    int main(void)
    {
        int num = 0;
        int *ptr = &num;
        printf("&#37;p\n", (void*)ptr);
        return 0;
    }
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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    thanks that worked.
    the only problem is that my assignement says that i have to use &#37;p to print hex.
    is there any othe way to print hex using %p

  14. #14
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    Quote Originally Posted by goran00 View Post
    thanks that worked.
    the only problem is that my assignement says that i have to use &#37;p to print hex.
    is there any othe way to print hex using %p
    I dont think you're meant to ask us to do your homework. I already posted how to do it like that anyways (look up)

  15. #15
    C++ Witch laserlight's Avatar
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    the only problem is that my assignement says that i have to use &#37;p to print hex.
    Your assignment instructions are correct.

    is there any othe way to print hex using %p
    My example and 39ster's most recent example both print using %p. 39ster's example just adds a "0x" in front, but that has no bearing on whether the address is actually printed in hex. What number base %p prints in is implementation defined, but hex is most likely.

    EDIT:
    the above program prints
    0012FF60
    i was looking to get it to print something with an x in the middle
    ex. 0x40tt
    0012FF60 is quite definitely a number expressed in hexadecimal. What you want is to add a "0x" in front, as demonstrated by 39ster. However, note that 39ster's example is not quite correct since 39ster neglected to cast the address to void*.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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