Drawing a circle with ASCII character

Hello,

i have to draw a circle with ASCII character. So far i got to this and now i'am stuck. Could somebody help me please? The "." is just to give me a better overview, in the end i will replace that with " ".

Code:

#include <stdio.h>

void line (int r);
void vertical (int r);


int main()
{
	int r;
	
	printf("radius: ");
	scanf("%d", &r);
	
	line(r);
	printf("\n");
	vertical(r-1);
	printf("\n");
	line(r);
	
	return 0;
}

void line(int r)
{
	int i,j;
	
	for ( i=1; i<=r-1; i++){
		if( (r-i)>=2 )
			printf(".");
		else{
			for(j=0;j<3;j++)
				printf("x");
		}
	}
}

void vertical(int r)
{
	int i,j,k;
	
	for ( i=1; i<=r-1; i++){
		if( (r-i)>=2 )
			printf(".\n");
		else{
			for(j=0;j<3;j++)
				printf("x\n");
			for(k=0; k<r-2; k++){
				printf("\n");
				printf(".");
			}
		}
		
	}	
}

Thank you in advance.
bnk

Heres some code for drawing a filled circle, I'm pretty sure its the same algo used in MS paint as it leaves a pointy out pixel. Anyway nevermind about that, the good thing about this algo is that it draws your circle in scanlines, which is ideal for console output. You might want to add some offset for x, and use putchar instead of wirtepixel, that should work.

Code:

for(y=-radius; y<radius; y++)
{
    half_row_width=sqrt(radius*radius-y*y);
    for(x=-half_row_width; x< half_row_width; x++)
        WritePixel(centre_x+x, centre_y+y, colour);
}

Thank you. I will play with this a bit.

mike: the code is very easy to follow. thanks.
and i only knew how to draw outline circles, which is more difficult the way i do, but this is very easy.

Thank you. I will play with this a bit.

Me too!

Draw a circle with ASCII:

Code:

printf("O");

Originally Posted by brewbuck

Draw a circle with ASCII:

Code:

printf("O");

Hehe.

Is your code for drawing a circle in ASCII taking into account the fact that ASCII characters are rectangles? If you don't scale they Y appropriately you may be looking at an oval.

Hi again. I did play around with it a bit and this is what i did. What i forgot to tell you i cant use any other library then stdio.h.

Code:

#include <stdio.h>

int main()
{
	int i,j,radius;

	printf("Radius is: ");
	scanf("%d", &radius);

	for (j=0; j<2*radius; j++)
	{
		for(i=1; i<2*radius; i++)
		{
			if(i>radius-2 && i<radius+2)
				printf("x");
			else
				printf(".");
		}
		printf("\n");
	}

	return 0;
}

Thats what i got. I think i have to do something with the if statement for x so that i would print the character at the right place on the y coordinate. Could somebody give me any pointers ?!

guesst wrote

Is your code for drawing a circle in ASCII taking into account the fact that ASCII characters are rectangles? If you don't scale they Y appropriately you may be looking at an oval.

You are absolutly right, but i dont have to draw a perfect circle.


Thank you.

You could draw a bresenham circle using only the functions in stdio. The algorithm draws cirles in four corners. So in your case you would have to draw the top two first at the same time, then the bottom two. You should be able to find an example if you google it.

Originally Posted by mike_g

You could draw a bresenham circle using only the functions in stdio. The algorithm draws cirles in four corners. So in your case you would have to draw the top two first at the same time, then the bottom two. You should be able to find an example if you google it.

An even more optimal algorithm only computes 1/8th of the circle, and rotates/reflects it to produce the other 7/8ths. I can't remember what it's called -- perhaps it's also called Bresenham, though a slightly different method.

I think i've did it. I just looked at my fist post and i have to say i'am really srry but i didn't write what i have to do right. I dont have to draw a circle but an circular line. Srry english is not my maternal language. So now let's get back to the problem.

In the If statement i have to implement the pythagoras theorem: x^2+y^2=r^2 and every point that is over or under the vaule I'am going to putchar( ) everything else is goint to be an (x) or something else.

Thank you all for helping.

brewbuck: oh yeah, it was 8ths wasent it. I forgot, been a while since I last looked at it.

bnkslo: yeah the only problem is that to get the square root you need math.h, unless you write your own function to do this.

Mike you are right. I just wrote this:

Code:

int main()
{
	int i,j,radij;
	
	printf("Put in radij: ");
	scanf("%d", &radij);
	
	if(radij>0 && radij<80)
	{
		for (j=0; j<=2*radij; j++)
		{
			for (i=0; i<=2*radij; i++)
			{
				if ((j*j+i*i<=2*radij) && (j*j+i*i>=2*radij))
					printf("x");
				else
					printf(".");
			}	
			printf("\n");
		}
	}
	else
	      printf("Wrong radij!");
	
	return 0;
}

and this is what came out:

...........
...x.......
...........
.x.........
...........
...........
...........
...........
...........
...........
...........

If I understod right you mean i have to write a function so that i have a point from where I'am goint to calculate the circular line? Like a center of the circle?

I already saw some totaly dum mistake like 2*r=r^2 I mean and some other miner mistakes here and there...

Well first off if you dont get the square root the circle will end up being very big and in most cases too big to display properly in the console.

For each scanline you could get your x offset before you start plotting your circle dots. Then draw that amount of blanks, then draw as many x's as needed followed by a newline.

Edit; the -rad to +rad bit is important. It wont work correctly from 0 to rad*2.

Mike you were right the magic word was offset i have to treat it like the circle mid point is not in the top left corner.