Rather than having to input :
If (number= (100*1)+10){
printf("number times a hundred plus ten");
If(number=(100*1)+10){
printf("number times a hundred plus ten");
etc...
Isn't there a way i can condense that into one IF with an Or ||... i've tired it but what ends up happening is any number sent to this subroutine prints the message even though i only want it to print if it specifically meets ((100*1)+10) or ((100*2)+10) etc.
What am i doing wrong ?
Please and thank you.
= is assignment
== is comparison
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
Oops, my mistake i meant ==, but yeh even then the problem occurs. Cant i set multiple parameters in a single IF ? If so, how ?
Please post your ACTUAL code, not paraphrased code.
--
Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
If (number= =(100*1)+10){
printf("number times a hundred plus ten");
If(number==(100*1)+10){
printf("number times a hundred plus ten");
Although paraphrased this is essentially the exact same, all i want to know is if i can convert the two IFs above into just one.
If (number= =(100*1)+10) AND HAVE THIS IN HERE TOO (number==(100*1)+10){
printf("number times a hundred plus ten");
They test the same condition, so you could write:
If they were different, you could join them with an || (or).Code:if (number == (100*1)+10) { printf("number times a hundred plus ten"); printf("number times a hundred plus ten"); }
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
Is the same asCode:if (condition1) if (condition2) some_code;
If condition1 AND condition2Code:if (condition1 && condition2) some_code;
It's also possible to do:
If condition1 OR condition 2.Code:if (condition1 || condition2) some_code;
